Experimental Chemistry review
Review separation, chromatography and purity decisions at G2 depth.
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The core idea
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Learning objectives
Show all 14 objectives
- name appropriate apparatus for the measurement of time, temperature, mass and volume; including burettes, pipettes, measuring cylinders and gas syringes
- suggest suitable apparatus, given relevant information, for a variety of simple experiments, including collection of gases.
- describe methods of separation and purification for the components of mixtures, to include: — use of a suitable solvent, filtration and crystallisation or evaporation
- describe methods of separation and purification for the components of mixtures, to include: — distillation and fractional distillation (see also 8.1(b))
- describe methods of separation and purification for the components of mixtures, to include: — paper chromatography
- suggest suitable separation and purification methods, given information about the substances involved in the following types of mixtures: — solid-solid
- suggest suitable separation and purification methods, given information about the substances involved in the following types of mixtures: — solid-liquid
- suggest suitable separation and purification methods, given information about the substances involved in the following types of mixtures: — liquid-liquid (miscible)
- interpret paper chromatograms including comparison with ‘known’ samples (the use of Rf values is not required)
- deduce from given melting point and boiling point data the identities of substances and their purity.
- select and use techniques, apparatus and materials
- take readings and record observations
- interpret and evaluate experimental data and observations
- evaluate methods and suggest possible improvements.
Experimental methods
An experimental method earns marks when every apparatus choice has a reason. Name the quantity, choose an instrument with a suitable range and precision, and state how the result will be read or collected.
1. Definition
An experimental method is an ordered, safe procedure for making observations or measurements that answer a question. A measurement is a numerical value recorded with its unit.
2. Key Ideas
- Measure time with a stopwatch or data logger, temperature with a thermometer, mass with a balance, and volume with suitable volumetric apparatus.
- A measuring cylinder is suitable for approximate liquid volumes; a pipette or burette is used when greater precision is required.
- A gas syringe measures gas volume directly.
- Collect a gas over water only if it is not very soluble in water.
- Use displacement of air when water is unsuitable, choosing the jar orientation from the gas density.
- Read a liquid scale at eye level and record the instrument’s precision.
- In an acid–alkali titration, use a pipette for a fixed volume, a burette for a measured variable volume and the given indicator to show the end-point.
3. Detailed Explanations
Selecting an instrument
First identify the quantity and expected range. Then choose the smallest useful scale divisions without exceeding the instrument range. For a change found from two readings:
For reaction-rate measurements, keep time intervals consistent and measure a quantity such as gas volume or mass loss.
Collecting gases
Collection over water is convenient when the gas has low solubility and does not react with water. If water is unsuitable, use density to choose the jar orientation:
- upward delivery collects a gas less dense than air in an inverted gas jar; the gas rises and pushes air downwards;
- downward delivery collects a gas denser than air in an upright gas jar; the gas sinks and pushes air upwards.
A gas syringe avoids relying on density and gives a volume reading, but connections must be gas-tight.
Carrying out an acid–alkali titration
Rinse the pipette with the solution it will transfer, then use it to place a fixed volume in a conical flask. Add the suitable given indicator. Rinse and fill the burette with the other solution, remove the funnel, record the initial reading and add solution while swirling the flask. Near the end-point, add it drop by drop until the indicator changes colour permanently. Record the final burette reading and calculate the volume delivered. Repeat until close results are obtained. Focus here on the apparatus, safe method, readings and end-point; use the Chemical Calculations lesson for any calculation based on titration data.
Main titration setup
Transfer the measured volume safely
4. Common Mistakes
- Do not write “measure the liquid” without naming volume and the apparatus.
- Do not read a scale from above or below eye level.
- Do not collect a water-soluble gas over water.
- Do not ignore gas leaks, which make a collected volume too small.
- Do not give a reading without its unit.
- Do not use a measuring cylinder in place of a pipette when an accurate fixed volume is required for titration.
- Do not add large portions near the end-point; add solution dropwise while swirling.
5. Exam Tips
Exam question 1: Match precision to purposeCore
A student must transfer exactly 25.0 cm³ of solution. Name the most suitable apparatus and explain the choice.
Show Answer
Use a 25.0 cm³ volumetric pipette. It transfers one fixed volume more precisely than a measuring cylinder.
Exam question 2: Approach a titration end-pointCore
Explain two changes to the method as the indicator begins to change colour near the end-point.
Show Answer
Add the burette solution drop by drop and swirl the conical flask after each addition. This prevents one large addition from passing the end-point before the colour is mixed throughout the solution.
Use the pattern quantity → apparatus → reading or collection method → unit.
6. Worked Examples
Modelled example 1
Choose a Gas-Collection Method
Problem
Study the worked solution
Reject collection over water
Method
Do not collect the gas over water.Reason
A very soluble gas would dissolve, so little of it would remain in the collection vessel.Working
Water collection: unsuitable.Use density
Method
Use downward delivery into an upright gas jar, with the delivery tube entering low in the jar.Reason
The denser gas sinks and displaces the less-dense air upwards.Working
Method: downward delivery (upward displacement of air).
Guided practice 2
Calculate a Delivered Volume
Problem
Try this before viewing the solution
Hints
Hint 1: change rule
Hint 2: precision
View solution step by step
Find the change
Method
Subtract the initial reading from the final reading.Reason
Delivered volume is the change between the two scale readings.Working
24.65-1.20 = 23.45.Attach unit and precision
Method
Report the value in cubic centimetres to two decimal places.Reason
The original readings justify that precision.Working
23.45 cm³.
Common misconception 3
A Leak Does Not Increase the Syringe Reading
Learner claim
Try this before viewing the solution
View solution step by step
Follow the product gas
Method
State that some newly formed gas escapes through the loose connection.Reason
The leak gives the gas another path instead of forcing all of it into the syringe.Working
Gas reaching syringe < gas produced.State the error direction
Method
Conclude that the measured collected volume is too small.Reason
The syringe records only the gas that reaches it.Working
Leak → underestimated gas volume.
Examiner practice 4
Match Volume Apparatus to Purpose
Examination question
Try this before viewing the solution
View solution step by step
Choose for the fixed exact volume
2 marksMethod
Use a 25.0 cm³ volumetric pipette.Reason
It transfers one calibrated fixed volume more precisely than a measuring cylinder.Working
Exact fixed transfer: volumetric pipette.Choose for the approximate variable volume
2 marksMethod
Use a suitably sized measuring cylinder.Reason
It can measure approximately 35 cm³ and its precision is sufficient when an exact fixed volume is not required.Working
Approximate volume: measuring cylinder, read at eye level.
Self-mark with the mark scheme
Compare your response with each mark point. Select a point only when your response contains that evidence.
Self-mark each instrument beside its purpose-linked reason.
Challenge 5
Collect a Lighter Water-Soluble Gas
Problem
Try this before viewing the solution
Hints
Hint 1: solubility first
Hint 2: density direction
View solution step by step
Reject water
Method
Reject collection over water.Reason
Gas X is very soluble and would dissolve instead of accumulating.Working
Use displacement of air.Orient the jar
Method
Use upward delivery into an inverted gas jar.Reason
The less-dense gas rises into the jar and displaces denser air downwards.Working
Less dense than air → upward delivery.
7. Mind Stretchers
Mind stretcher 1: Improve a gas-volume experimentExtension
Why should the stopper be fitted before the reactants are mixed in a gas-volume experiment?
Show Answer
Gas may form immediately. Sealing first prevents early gas from escaping before it reaches the gas syringe.
Mind stretcher 2: Balance range and precisionExtension
Why is the instrument with the finest scale not automatically the best choice?
Show Answer
Its range may be too small for the expected value. The instrument must cover the whole range while still giving suitable precision.
8. Quiz
Before attempting the assessment, check that you can:
- select apparatus for time, temperature, mass and volume;
- explain a choice using range and precision;
- read a scale correctly with units;
- select gas collection from solubility and density;
- carry out an acid–alkali titration using a pipette, burette and given indicator;
- identify and prevent gas loss.
Try this next: choose an unfamiliar gas from supplied solubility and density data, then write a one-sentence justification for its collection method.
Separation and purity
Choose a separation method from a difference in physical properties. State what passes through, what remains, and how the required substance is recovered.
1. Definition
Separation divides a mixture without forming new substances. Purification removes unwanted substances. A pure substance contains one substance and has characteristic physical properties.
2. Key Ideas
- Filtration separates an insoluble solid from a liquid.
- Crystallisation obtains a dissolved solid without heating the solution to dryness.
- Simple distillation obtains a solvent from a solution.
- Fractional distillation separates miscible liquids with different boiling points.
- Paper chromatography separates soluble substances because they travel differently with a solvent.
- A pure substance melts or boils sharply at its characteristic temperature.
3. Detailed Explanations
Match method to evidence
Use filtration when particle size and insolubility differ. Use crystallisation when a solid is soluble and may decompose on strong heating. Use distillation when volatility or boiling point differs.
Swipe or scroll sideways to inspect the complete overview.
For a solid–solid mixture, choose a solvent that dissolves only one solid. Add the solvent, stir, filter, and wash and dry the insoluble residue. Recover the dissolved solid from the filtrate by crystallisation or evaporation. For a solid–liquid mixture, filter if the solid is insoluble; if it is dissolved, use crystallisation, evaporation or distillation according to the product required. For miscible liquids, use fractional distillation when their boiling points differ.
Choose evaporation when the solvent is not required and the dissolved solid is stable on heating. Choose crystallisation when crystals are wanted or heating to dryness could decompose the solid. Choose simple distillation when the solvent itself must be collected.
Carry out simple and fractional distillation
For simple distillation, heat the solution so that the more volatile liquid boils. Its vapour enters the condenser, cools and changes back to liquid. Collect this liquid as the distillate; the less volatile dissolved substance remains in the flask. Keep the thermometer bulb level with the side arm so it measures the vapour entering the condenser. Cooling water enters the lower condenser port and leaves from the upper port, keeping the water jacket full.
Swipe or scroll sideways to inspect the complete overview.
For fractional distillation, place a fractionating column between the heated flask and condenser. Repeated condensation and vaporisation in the column allow vapour richer in the lower-boiling liquid to reach the condenser first. Use this method for miscible liquids, especially when their boiling points are close enough that simple distillation would separate them poorly.
Swipe or scroll sideways to inspect the complete overview.
Do not heat a closed apparatus. The receiver remains open to the air so pressure cannot build up.
Set up and read paper chromatography
In chromatography, place the sample on a pencil baseline above the solvent. The solvent moves through the paper and carries components different distances. Here, interpret the number of spots and their positions compared with known samples. Where your syllabus also requires calculated R_f values, the methods of separation and purification lesson teaches that calculation.
Swipe or scroll sideways to inspect the complete overview.
Judge purity
An impurity usually lowers and broadens a solid’s melting range. A pure liquid boils at a sharp characteristic temperature at a stated pressure. One chromatogram spot supports purity only for the solvent and locating conditions used.
4. Common Mistakes
- Filtration cannot remove a dissolved solute.
- Evaporation to dryness is not the safest way to obtain every soluble solid.
- The chromatography baseline must be pencil, not ink.
- The sample spot must begin above the solvent level.
- “High melting point” does not prove purity; use a sharp characteristic value.
5. Exam Tips
Exam question 1: Separate with the required product in mindCore
A mixture contains sand, salt and water. Describe how to obtain dry sand and pure water.
Show Answer
Filter the mixture. Wash and dry the residue to obtain sand. Distil the filtrate and collect the condensed solvent as pure water.
Use the pattern property difference → method → named apparatus action → product obtained.
Exam question 2: Use melting data to identify purityCore
Pure solid A melts at 80 °C and pure solid B melts at 122 °C. A sample melts sharply at 121–122 °C. Another sample melts over 116–121 °C. Identify the first sample and comment on the second.
Show Answer
The first sample is consistent with pure B because it melts sharply at B’s characteristic temperature. The second sample is impure B: its melting range is lower and broader.
6. Worked Examples
Modelled example 1
Recover a Soluble Solid
Problem
Study the worked solution
Concentrate the solution
Method
Heat gently to evaporate some water until nearly saturated.Reason
Removing some solvent prepares the solution to crystallise on cooling without heating the salt to dryness.Working
Gentle evaporation → nearly saturated solution.Form and collect crystals
Method
Cool, then filter the crystals.Reason
Solubility falls on cooling and the crystals become a solid residue.Working
Cool → crystallise → filter.Purify and dry
Method
Wash with a little cold distilled water and dry between filter papers.Reason
Cold water removes adhering solution while limiting crystal loss.Working
Washed, dry copper(II) sulfate crystals.
Guided practice 2
Choose Between Simple and Fractional Distillation
Problem
Choose and justify
Hints
Hint 1: mixture type
Hint 2: boiling evidence
View solution step by step
Choose the method
Method
Use fractional distillation.Reason
P and Q are miscible liquids with different, fairly close boiling points.Working
Mixture type + boiling-point evidence → fractional distillation.Explain the column
Method
Use a fractionating column before the condenser.Reason
Repeated condensation and vaporisation make the vapour reaching the condenser richer in the lower-boiling liquid P.Working
P distils first near 78 °C.
Guided practice 3
Interpret Chromatogram Spots
Problem
Separate both conclusions
Hints
Hint 1: count
Hint 2: compare
View solution step by step
Use spot count
Method
Infer that the unknown is a mixture.Reason
It separates into two visible components under these conditions.Working
Two spots → mixture.Use alignment
Method
State that its components are consistent with A and B.Reason
Each unknown spot aligns with one reference in the same chromatogram.Working
Contains components consistent with A and B.
Common misconception 4
Do Not Filter a Dissolved Solute
Learner plan
Track the dissolved salt
View solution step by step
Reject filtration
Method
State that dissolved salt passes through the filter.Reason
Its particles are not an insoluble solid trapped by filter paper.Working
Residue: none of the dissolved salt; filtrate: salt solution.Choose crystallisation
Method
Concentrate and cool the solution, then collect and dry crystals.Reason
The method uses the solute’s changing solubility as solvent is removed and temperature falls.Working
Crystallisation recovers the salt.
Examiner practice 5
Recover Sand and Pure Water
Examination question
Write the method in order
View solution step by step
Separate sand
1 markMethod
Filter the mixture.Reason
Sand is insoluble and remains as residue.Working
Sand residue; salt solution filtrate.Finish the sand
1 markMethod
Wash the residue and dry it.Reason
Washing removes adhering salt solution.Working
Dry sand obtained.Recover water
2 marksMethod
Distil the filtrate and collect the condensed liquid.Reason
Water vaporises and condenses while dissolved salt remains in the flask.Working
Distillate: pure water.
Self-mark with the mark scheme
Compare your response with each mark point. Select a point only when your response contains that evidence.
Award method points only in a workable order.
Challenge 6
Choose Methods for an Ink Mixture
Two-goal transfer
Match method to goal
Hints
Hint 1: water
Hint 2: dyes
View solution step by step
Recover the solvent
Method
Use simple distillation and collect the condensed water.Reason
Water is volatile while the dyes remain in the flask.Working
Pure-water product: distillate.Analyse the dyes
Method
Use paper chromatography and count separated visible spots.Reason
Dyes move different distances with the solvent under the chosen conditions.Working
Number of spots → number of visible separated components under those conditions.
7. Mind Stretchers
Mind stretcher 1: Question one-spot evidenceExtension
Why does one spot not prove that a sample is pure in every possible test?
Show Answer
Two components can travel together in one solvent or may not be visible with one locating method. A different solvent or locating condition may separate them.
Mind stretcher 2: Explain repeated separationExtension
Why does a fractionating column improve the separation of miscible liquids with fairly close boiling points?
Show Answer
Repeated condensation and vaporisation enrich the rising vapour in the more volatile liquid before it reaches the condenser.
Mind stretcher 3: Recover both solidsExtension
A mixture contains soluble salt and insoluble sand. Describe how to obtain both substances dry, starting with a suitable solvent.
Show Answer
Add water and stir so the salt dissolves. Filter the mixture, then wash and dry the sand residue. Concentrate the salt solution, cool it to crystallise the salt, filter the crystals, wash them with a little cold water and dry them.
8. Quiz
Before attempting the assessment, check that you can:
- select a method from solubility, boiling point or particle-size evidence;
- use a suitable solvent to separate two solids and recover both products;
- distinguish residue, filtrate, distillate and crystals;
- explain a paper chromatography setup and chromatogram;
- use melting and boiling behaviour as purity evidence;
- state the limits of one purity test.
Practise this: for each new mixture, write four parts before naming a method: the mixture type, the physical-property difference, the required product and the apparatus action.