Salts
Salts: definitions, formulae, solubility rules, precipitate prediction and selecting excess-solid, titration or precipitation methods.
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The core idea
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Learning objectives
- describe the general rules of solubility for common salts to include nitrates, chlorides (including those of silver and lead), sulfates (including those of barium, calcium and lead), carbonates, hydroxides, salts of Group 1 cations and ammonium salts
- suggest a method of preparing a given salt from suitable starting materials, given appropriate information.
A salt question may ask you to move between a name, an ionic formula, a solubility prediction and a practical preparation method. Keep those decisions connected.
1. Definition
A. Salt
A salt is an ionic compound formed when the H⁺ ion in an acid is replaced by a metal ion or an ammonium ion, NH₄ +.
2. Key Ideas
- Salt names are made from:
- the cation (metal or ammonium), and
- the anion from the acid (chloride, sulfate, nitrate, ethanoate, carbonate, etc.).
Acid name → salt anion (memorise these):
| Acid | Formula | Salt name ends with | Anion |
|---|---|---|---|
| hydrochloric acid | HCl | chloride | Cl⁻ |
| nitric acid | HNO₃ | nitrate | NO₃⁻ |
| sulphuric acid | H₂SO₄ | sulfate | SO₄²⁻ |
| ethanoic acid | CH₃COOH | ethanoate | CH₃COO⁻ |
- Solubility rules let you predict whether a salt remains dissolved or forms a precipitate; practise applying the exceptions rather than guessing.
3. Detailed Explanations
- Salt = H⁺ in an acid replaced by a metal ion or NH₄ +.
- Name = cation + anion (chloride/sulfate/nitrate/carbonate/ethanoate…).
- Always soluble: all nitrates, all ammonium salts and all Group 1 salts.
- Key exceptions: AgCl and PbCl₂ (insoluble chlorides); BaSO₄, PbSO₄, CaSO₄ (insoluble/sparingly soluble sulfates).
A. Where the “two parts” come from
In many salt-making reactions:
- the cation comes from the metal/base, and
- the anion comes from the acid.
Example: KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)
Here, K⁺ comes from KOH and Cl⁻ comes from HCl, so the salt is potassium chloride, KCl.
B. Common ways salts are formed (O-Level)
| Reaction type | What you write | Example |
|---|---|---|
| acid + metal | salt + hydrogen | Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g) |
| acid + metal oxide/hydroxide | salt + water | CuO(s) + 2HCl(aq) → CuCl₂(aq) + H₂O(l) |
| acid + alkali | salt + water | NaOH(aq) + HNO₃(aq) → NaNO₃(aq) + H₂O(l) |
| acid + carbonate | salt + water + carbon dioxide | CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g) |
Do not write “acid + base → salt + water” as an absolute rule.
Ammonia forms ammonium salts without water:
NH₃(aq) + HCl(aq) → NH₄Cl(aq)
C. Solubility rules (the ones examiners expect)
Solubility rules tell you whether a salt is soluble in water (aq) or forms a precipitate (s).
| Salt type | Usually soluble? | Common exceptions (memorise) |
|---|---|---|
| nitrates (NO₃⁻) | yes | none (at O-Level) |
| ammonium salts (NH₄ +) | yes | none |
| Group 1 salts (Li⁺, Na⁺, K⁺) | yes | none |
| chlorides (Cl⁻) | yes | AgCl, PbCl₂ |
| sulfates (SO₄²⁻) | yes | BaSO₄, PbSO₄, CaSO₄ (sparingly soluble) |
| carbonates (CO₃²⁻) | no | Group 1 carbonates + ammonium carbonate are soluble |
| hydroxides (OH⁻) | no | Group 1 hydroxides are soluble; Ca(OH)₂ is sparingly soluble |
Solubility rules appear constantly in qualitative analysis (precipitate formation): Qualitative Analysis (QA).
D. Choosing a preparation method (don’t lose yield)
The best method depends on whether the salt is soluble or insoluble.
| Salt type | Preparation idea | Why |
|---|---|---|
| soluble salt | use excess insoluble solid + acid, then filter + crystallise | easy to remove excess solid |
| soluble salt (acid + alkali) | titration then crystallise | you cannot “filter out excess alkali” |
| insoluble salt | mix two solutions to form a precipitate, then filter + wash + dry | salt forms as a solid |
Preparation steps and which reagents to choose: Preparation of Soluble Salts & Insoluble Salts.
E. Keep the three representations separate
For the precipitation of silver chloride:
- Macroscopic: a white precipitate is seen.
- Particle level: aqueous Ag⁺ and Cl⁻ ions form an insoluble ionic lattice; spectator ions remain in solution.
- Symbolic: Ag + (aq) + Cl⁻(aq) → AgCl(s).
An observation describes what is seen. It should not be replaced by a particle explanation or an equation.
4. Common Mistakes
- Thinking “salt” means only NaCl.
- Using the wrong solubility exception (learn the chloride/sulfate/carbonate exceptions).
- Saying “do titration” for every salt (wrong): titration is specifically for soluble salts made from acid + alkali.
5. Exam Tips
- State the solubility rule, then name the precipitate (if any).
- For preparation, justify the method by extraction: “use excess solid so I can filter it off.”
- If asked to predict a precipitate when two solutions are mixed: write the insoluble salt and label it (s).
- Always include state symbols if the question expects them.
6. Worked Examples
Modelled example 1
Identify the salt from the reactants
Problem
Study the worked solution
Identify the cation
Method
Take sodium ions from sodium hydroxide.Reason
The base supplies the positive ion in the salt.Working
Cation: Na⁺.Identify the acid anion
Method
Take sulfate ions from sulfuric acid.Reason
The acid determines the salt-family ending.Working
Anion: SO₄²⁻; salt family: sulfate.Balance charges and name
Method
Combine two sodium ions with one sulfate ion.Reason
Total positive and negative charges must cancel.Working
Sodium sulfate, Na₂SO₄.
Guided practice 2
Predict if a precipitate forms (chloride exception)
Problem
Apply the exception, not only the general rule
Hints
Hint 1: chloride rule
Hint 2: combine the ions
View solution step by step
Identify the possible products
Method
Pair Ag⁺ with Cl⁻.Reason
Mixing the solutions brings those ions together.Working
Candidate product: AgCl.Apply the exception
Method
Classify silver chloride as insoluble.Reason
It is an exception to the usual solubility of chlorides.Working
Silver chloride, AgCl(s), precipitates.
Common misconception 3
Carbonate rule
Learner claim
Check the allowed exceptions
View solution step by step
State the carbonate rule
Method
Begin with carbonates being insoluble.Reason
Only Group 1 and ammonium carbonates are the stated soluble exceptions.Working
Carbonates: insoluble except Group 1 and NH₄ + salts.Test calcium against the exceptions
Method
Place calcium in Group 2.Reason
It matches neither soluble exception.Working
CaCO₃ is insoluble.
Examiner practice 4
Sulfate exception
Examination question
Name and formulate the insoluble product
View solution step by step
Name the precipitate
1 markMethod
Combine barium and sulfate names.Reason
Those are the ions that form the insoluble product.Working
Barium sulfate.Give formula and state
1 markMethod
Write a 1:1 neutral formula with (s).Reason
Ba²⁺ and SO₄²⁻ balance, and a precipitate is solid.Working
BaSO₄(s).
Self-mark with the mark scheme
Compare your response with each mark point. Select a point only when your response contains that evidence.
Self-mark name and state-labelled formula.
Challenge 5
Choose the preparation method (acid + alkali)
Method-selection transfer
Use the separation constraint
Hints
Hint 1: can excess be filtered
Hint 2: find exact volumes
View solution step by step
Identify the separation problem
Method
Recognise that both reactants are aqueous.Reason
An excess of either would remain dissolved and contaminate the salt solution.Working
Excess acid/alkali cannot be removed by filtration.Select and complete the method
Method
Use titration, repeat without indicator, then concentrate and crystallise.Reason
Exact neutralising volumes leave no excess reactant in the soluble salt solution.Working
Titration → neutral solution → crystallisation of NaNO₃.
7. Mind Stretchers
Mind stretcher 1: Fix the student’s claimExtension
Question: A student writes: “All chlorides are insoluble.” Correct this with one exception example.
Show Answer
Chlorides are usually soluble. Exceptions include silver chloride, AgCl(s), and lead(II) chloride, PbCl₂(s).
Mind stretcher 2: Extraction logicExtension
Question: Why is “acid + excess insoluble base” a good method for preparing some soluble salts?
Show Answer
Because the excess base is a solid and can be filtered off, leaving only the salt solution to be crystallised. This avoids excess acid contaminating the product.
8. Quiz
Test yourself on definitions, solubility rules, precipitate prediction, and selecting preparation methods.