Separation and purity

Separation and purity

  • SEC G3 Combined Science Chemistry component 2027
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Learning objectives

  • describe methods of separation and purification for the components of mixtures, to include: — use of a suitable solvent, filtration and crystallisation or evaporation
  • describe methods of separation and purification for the components of mixtures, to include: — distillation and fractional distillation (see also 11.1(b))
  • describe methods of separation and purification for the components of mixtures, to include: — paper chromatography
  • suggest suitable separation and purification methods, given information about the substances involved in the following types of mixtures: — solid-solid
  • suggest suitable separation and purification methods, given information about the substances involved in the following types of mixtures: — solid-liquid
  • suggest suitable separation and purification methods, given information about the substances involved in the following types of mixtures: — liquid-liquid (miscible)
  • interpret paper chromatograms including comparison with ‘known’ samples (the use of Rf values is not required)
  • deduce from given melting point and boiling point data the identities of substances and their purity.

Choose a separation method from a difference in physical properties. State what passes through, what remains, and how the required substance is recovered.

1. Definition

Separation divides a mixture without forming new substances. Purification removes unwanted substances. A pure substance contains one substance and has characteristic physical properties.

2. Key Ideas

  • Filtration separates an insoluble solid from a liquid.
  • Crystallisation obtains a dissolved solid without heating the solution to dryness.
  • Simple distillation obtains a solvent from a solution.
  • Fractional distillation separates miscible liquids with different boiling points.
  • Paper chromatography separates soluble substances because they travel differently with a solvent.
  • A pure substance melts or boils sharply at its characteristic temperature.

3. Detailed Explanations

Match method to evidence

Use filtration when particle size and insolubility differ. Use crystallisation when a solid is soluble and may decompose on strong heating. Use distillation when volatility or boiling point differs.

Filtration apparatusA filter funnel lined with filter paper sits over a conical flask. Insoluble residue remains on the paper while filtrate collects in the flask.filter paperresiduefiltrateinsoluble solid + liquid
Filtration: the insoluble solid remains as residue on the filter paper; the liquid passes through as filtrate.

For a solid–solid mixture, choose a solvent that dissolves only one solid. Add the solvent, stir, filter, and wash and dry the insoluble residue. Recover the dissolved solid from the filtrate by crystallisation or evaporation. For a solid–liquid mixture, filter if the solid is insoluble; if it is dissolved, use crystallisation, evaporation or distillation according to the product required. For miscible liquids, use fractional distillation when their boiling points differ.

Choose evaporation when the solvent is not required and the dissolved solid is stable on heating. Choose crystallisation when crystals are wanted or heating to dryness could decompose the solid. Choose simple distillation when the solvent itself must be collected.

Carry out simple and fractional distillation

For simple distillation, heat the solution so that the more volatile liquid boils. Its vapour enters the condenser, cools and changes back to liquid. Collect this liquid as the distillate; the less volatile dissolved substance remains in the flask. Keep the thermometer bulb level with the side arm so it measures the vapour entering the condenser. Cooling water enters the lower condenser port and leaves from the upper port, keeping the water jacket full.

Simple distillation apparatusA heated round-bottom flask connects to a still head. The thermometer bulb is level with the condenser entrance. Vapour passes into a downward-sloping water condenser, with cooling water entering at the lower port and leaving at the upper port, before the distillate collects in an open receiver.electric heater / hot-water bathmixturethermometerbulb level with side armwater condenserwater outwater indistillatereceiver open to air
Simple distillation: the thermometer bulb sits beside the condenser entrance, and cooling water enters the condenser at the lower port.

For fractional distillation, place a fractionating column between the heated flask and condenser. Repeated condensation and vaporisation in the column allow vapour richer in the lower-boiling liquid to reach the condenser first. Use this method for miscible liquids, especially when their boiling points are close enough that simple distillation would separate them poorly.

Fractional distillation apparatusA heated round-bottom flask connects through a fractionating column to a still head. The thermometer bulb is level with the condenser entrance. Vapour passes into a downward-sloping water condenser, with cooling water entering at the lower port and leaving at the upper port, before the distillate collects in an open receiver.electric heater / hot-water bathmixturefractionating columnthermometerbulb level with side armwater condenserwater outwater indistillatereceiver open to air
Fractional distillation: a fractionating column provides repeated condensation and vaporisation before vapour reaches the condenser.

Do not heat a closed apparatus. The receiver remains open to the air so pressure cannot build up.

Set up and read paper chromatography

In chromatography, place the sample on a pencil baseline above the solvent. The solvent moves through the paper and carries components different distances. Here, interpret the number of spots and their positions compared with known samples. Where your syllabus also requires calculated R_f values, the methods of separation and purification lesson teaches that calculation.

Paper chromatography setupPaper hangs in a covered beaker. The pencil start line and sample spots are above the solvent level, and separated spots lie below the marked solvent front.solvent frontpencil start linesolventseparated spotscovered container reduces solvent evaporation
Keep the pencil baseline above the solvent. The solvent rises through the paper and separates soluble components into spots at different heights.

Judge purity

An impurity usually lowers and broadens a solid’s melting range. A pure liquid boils at a sharp characteristic temperature at a stated pressure. One chromatogram spot supports purity only for the solvent and locating conditions used.

4. Common Mistakes

Name the relevant property
  • Filtration cannot remove a dissolved solute.
  • Evaporation to dryness is not the safest way to obtain every soluble solid.
  • The chromatography baseline must be pencil, not ink.
  • The sample spot must begin above the solvent level.
  • “High melting point” does not prove purity; use a sharp characteristic value.

5. Exam Tips

Exam question 1: Separate with the required product in mindCore

A mixture contains sand, salt and water. Describe how to obtain dry sand and pure water.

Show Answer

Filter the mixture. Wash and dry the residue to obtain sand. Distil the filtrate and collect the condensed solvent as pure water.

Use the pattern property difference → method → named apparatus action → product obtained.

Exam question 2: Use melting data to identify purityCore

Pure solid A melts at 80 °C and pure solid B melts at 122 °C. A sample melts sharply at 121–122 °C. Another sample melts over 116–121 °C. Identify the first sample and comment on the second.

Show Answer

The first sample is consistent with pure B because it melts sharply at B’s characteristic temperature. The second sample is impure B: its melting range is lower and broader.

6. Worked Examples

Modelled example 1

Recover a Soluble Solid

Core

Problem

Explain how to obtain copper(II) sulfate crystals from its aqueous solution.
Study the worked solution
  1. Concentrate the solution

    Method

    Heat gently to evaporate some water until nearly saturated.

    Reason

    Removing some solvent prepares the solution to crystallise on cooling without heating the salt to dryness.

    Working

    Gentle evaporation → nearly saturated solution.
  2. Form and collect crystals

    Method

    Cool, then filter the crystals.

    Reason

    Solubility falls on cooling and the crystals become a solid residue.

    Working

    Cool → crystallise → filter.
  3. Purify and dry

    Method

    Wash with a little cold distilled water and dry between filter papers.

    Reason

    Cold water removes adhering solution while limiting crystal loss.

    Working

    Washed, dry copper(II) sulfate crystals.

Guided practice 2

Choose Between Simple and Fractional Distillation

About 5 min

Problem

Liquids P and Q are miscible. Their boiling points are 78 °C and 100 °C. Choose a method to separate them and explain the purpose of its extra apparatus.

Choose and justify

Method
Extra apparatus

Hints

Hint 1: mixture type
Both substances are liquids and they mix completely.
Hint 2: boiling evidence
Their different but fairly close boiling points provide the separation evidence.
View solution step by step
  1. Choose the method

    Method

    Use fractional distillation.

    Reason

    P and Q are miscible liquids with different, fairly close boiling points.

    Working

    Mixture type + boiling-point evidence → fractional distillation.
  2. Explain the column

    Method

    Use a fractionating column before the condenser.

    Reason

    Repeated condensation and vaporisation make the vapour reaching the condenser richer in the lower-boiling liquid P.

    Working

    P distils first near 78 °C.

Guided practice 3

Interpret Chromatogram Spots

About 5 min

Problem

An unknown gives two spots. One aligns with reference A and the other with reference B in the same chromatogram. What can be concluded?

Separate both conclusions

Unknown is
Components consistent with

Hints

Hint 1: count
Count the unknown’s separated spots.
Hint 2: compare
Compare positions only within the same solvent and run.
View solution step by step
  1. Use spot count

    Method

    Infer that the unknown is a mixture.

    Reason

    It separates into two visible components under these conditions.

    Working

    Two spots → mixture.
  2. Use alignment

    Method

    State that its components are consistent with A and B.

    Reason

    Each unknown spot aligns with one reference in the same chromatogram.

    Working

    Contains components consistent with A and B.

Common misconception 4

Do Not Filter a Dissolved Solute

Find and correct the mistake

Learner plan

A learner filters salt solution to obtain salt as the residue. Explain the error and choose a suitable recovery method.

Track the dissolved salt

Salt after filtration
Recovery method

View solution step by step
  1. Reject filtration

    Method

    State that dissolved salt passes through the filter.

    Reason

    Its particles are not an insoluble solid trapped by filter paper.

    Working

    Residue: none of the dissolved salt; filtrate: salt solution.
  2. Choose crystallisation

    Method

    Concentrate and cool the solution, then collect and dry crystals.

    Reason

    The method uses the solute’s changing solubility as solvent is removed and temperature falls.

    Working

    Crystallisation recovers the salt.

Examiner practice 5

Recover Sand and Pure Water

4 marks

Examination question

A mixture contains sand, salt and water. Describe how to obtain dry sand and pure water. [4 marks]

Write the method in order

View solution step by step
  1. Separate sand

    1 mark

    Method

    Filter the mixture.

    Reason

    Sand is insoluble and remains as residue.

    Working

    Sand residue; salt solution filtrate.
  2. Finish the sand

    1 mark

    Method

    Wash the residue and dry it.

    Reason

    Washing removes adhering salt solution.

    Working

    Dry sand obtained.
  3. Recover water

    2 marks

    Method

    Distil the filtrate and collect the condensed liquid.

    Reason

    Water vaporises and condenses while dissolved salt remains in the flask.

    Working

    Distillate: pure water.

Challenge 6

Choose Methods for an Ink Mixture

Minimal support

Two-goal transfer

A water-soluble ink contains several dyes. Choose one method to recover pure water from the ink and another to determine how many visible dye components it contains. Explain each choice.

Match method to goal

Recover water
Separate visible dyes

Hints

Hint 1: water
Use the difference in volatility to collect the solvent.
Hint 2: dyes
Use different movement with a solvent to form separate spots.
View solution step by step
  1. Recover the solvent

    Method

    Use simple distillation and collect the condensed water.

    Reason

    Water is volatile while the dyes remain in the flask.

    Working

    Pure-water product: distillate.
  2. Analyse the dyes

    Method

    Use paper chromatography and count separated visible spots.

    Reason

    Dyes move different distances with the solvent under the chosen conditions.

    Working

    Number of spots → number of visible separated components under those conditions.

7. Mind Stretchers

Mind stretcher 1: Question one-spot evidenceExtension

Why does one spot not prove that a sample is pure in every possible test?

Show Answer

Two components can travel together in one solvent or may not be visible with one locating method. A different solvent or locating condition may separate them.

Mind stretcher 2: Explain repeated separationExtension

Why does a fractionating column improve the separation of miscible liquids with fairly close boiling points?

Show Answer

Repeated condensation and vaporisation enrich the rising vapour in the more volatile liquid before it reaches the condenser.

Mind stretcher 3: Recover both solidsExtension

A mixture contains soluble salt and insoluble sand. Describe how to obtain both substances dry, starting with a suitable solvent.

Show Answer

Add water and stir so the salt dissolves. Filter the mixture, then wash and dry the sand residue. Concentrate the salt solution, cool it to crystallise the salt, filter the crystals, wash them with a little cold water and dry them.

8. Quiz

Before attempting the assessment, check that you can:

  • select a method from solubility, boiling point or particle-size evidence;
  • use a suitable solvent to separate two solids and recover both products;
  • distinguish residue, filtrate, distillate and crystals;
  • explain a paper chromatography setup and chromatogram;
  • use melting and boiling behaviour as purity evidence;
  • state the limits of one purity test.

Practise this: for each new mixture, write four parts before naming a method: the mixture type, the physical-property difference, the required product and the apparatus action.