Ions and electron counting

Use charge to infer electron loss or gain while keeping element identity fixed.

  • SEC G3 Combined Science Chemistry component 2027
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Learning objectives

  • deduce the numbers of protons, neutrons and electrons in atoms and ions given proton and nucleon numbers.

Your goal is to deduce electron counts and ion charges while keeping proton number—and therefore element identity—fixed.

1. Retrieve what you know

For a neutral atom, how are proton and electron counts related? Which count fixes the element’s identity?

Check the retrieval

A neutral atom has equal numbers of protons and electrons. Proton number fixes the element.

2. Atom-and-ion model

Ion formation changes electrons, not the nucleus. Compare proton and electron counts to decide whether one species is neutral or charged; compare proton and neutron counts between species to decide whether they are isotopes.

SpeciesProtonsNeutronsElectronsClassification evidence
²⁷₁₃Al131413neutral atom: equal proton and electron counts
²⁷₁₃Al³⁺131410ion of the same nuclide: three fewer electrons
³⁵₁₇Cl171817neutral atom: equal proton and electron counts
³⁷₁₇Cl⁻172018negative ion and an isotope of chlorine-35

A positive ion has lost electrons; a negative ion has gained electrons. Check every result using:

charge = protons-electrons

“Isotope” and “ion” answer different questions: neutron count establishes the isotope, while electron imbalance establishes the charge. A species can be both a particular isotope and an ion.

3. Modelled example: aluminium ion

Modelled example 1

Count particles in an aluminium ion

Core

Problem

Find the proton, neutron and electron counts in ²⁷₁₃Al³⁺.
Study the worked solution
  1. Read the nucleus

    Method

    Use Z = 13 and calculate A-Z.

    Reason

    Ion formation does not change the nucleus.

    Working

    Protons = 13; neutrons = 27-13 = 14.
  2. Apply the charge

    Method

    Remove three electrons from the neutral count.

    Reason

    A 3 + ion has three fewer electrons than protons.

    Working

    Electrons = 13-3 = 10; check: 13-10 = 3 +.

4. Guided attempt: chloride ion

Guided practice 2

Decode a chloride ion

About 4 min

Problem

Find the counts in ³⁵₁₇Cl⁻.

Try this before viewing the solution

Hints

Hint 1: nucleus first
Use proton and nucleon numbers before applying the charge.
Hint 2: negative charge
A negative ion has more electrons than protons.
View solution step by step
  1. Keep the nucleus fixed

    Method

    Use 17 protons and 18 neutrons.

    Reason

    The charge does not alter proton or neutron count.

    Working

    35-17 = 18 neutrons.
  2. Gain one electron

    Method

    Use 18 electrons.

    Reason

    One extra electron produces charge 1-.

    Working

    17-18 = -1.

5. Misconception contrast

Ion formation never changes proton number. A positive ion has lost, not gained, electrons. Two particles can have the same electron count and still be different elements because proton number—not electron number—fixes identity.

6. Changed-context transfer

Two particles each have 10 electrons. Particle P has 11 protons and particle Q has 9 protons. Identify each charge and decide whether they are the same element.

Show transfer feedback

P has charge 1 + because it has one fewer electron than protons. Q has charge 1- because it has one more electron than protons. They are different elements because their proton numbers differ.

7. Independent check

A particle has 12 protons, 13 neutrons and 10 electrons. Write its charge, explain whether electron loss or gain formed it, and state which count must remain unchanged for it to remain the same element.