Factors Affecting Rate of Reaction

Explain concentration, gas compression, solid particle size and temperature using collisions; compare rates with fair tests and graphs.

  • SEC G3 Pure Chemistry 2027
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This lesson builds on effective collisions and activation energy. Revise Collision Theory first if those ideas are unfamiliar.

1. Definition

Factors affecting rate of reaction are conditions that change how fast reactants are used up or products are formed by changing the number of effective collisions per unit time.

2. Key Ideas

  • Factors that increase rate do one (or both) of these:
    • increase collision frequency (more collisions per unit time), and/or
    • increase the proportion of collisions that are effective (energy ≥ Eₐ).
  • These are the syllabus factors:
    • Concentration (solutions) and pressure (gases): more particles per unit volume → more collisions per unit time.
    • Particle size (solids): smaller particles give a larger total surface area → more collisions at the surface per unit time.
    • Temperature: particles move faster and more particles have energy ≥ Eₐ.
  • Catalysts act through a different mechanism: see catalysts and enzymes.
Change consideredApplies toWhat changes?Explanation to include
Concentrationsolutionsparticles per unit volume ↑“more frequent collisions per unit time” → “more frequent effective collisions per unit time”
Compress reacting gas (fixed amount, constant T)gasesparticles per unit volume ↑“particles closer together” → “more collisions per unit time”
Smaller particle sizesolidstotal surface area and exposed particles ↑“larger total surface area” → “more collisions at the surface per unit time”
Temperaturemost reactionsspeed ↑; fraction with energy ≥ Eₐ ↑“move faster”, “more collisions per unit time”, “larger proportion have energy ≥ Eₐ”

3. Detailed Explanations

Choose the right causal chain
  • Concentration and gas compression change the number of reacting particles per unit volume.
  • Smaller solid pieces expose more surface for the same mass.
  • Temperature changes particle speeds and the fraction of collisions above the activation-energy barrier.
  • End each explanation with more frequent effective collisions per unit time.

A. Concentration (solutions)

For a reacting solute, increasing concentration means more reactant particles per unit volume. In the collision model, the rate increases because:

  • there are more reactant particles per unit volume,
  • particles are closer together,
  • so there are more frequent collisions per unit time,
  • so there are more frequent effective collisions per unit time (faster rate).
Do not write “more concentrated” without the particle idea

“More concentrated” is not the explanation. The explanation is “more reactant particles per unit volume → more collisions per unit time.”

Acid concentration and gas-production rate

Two illustrative cumulative gas-volume curves. Both reach 40 cm³ and remain there through 120 s. The higher-concentration trial reaches its plateau sooner.

Scroll across the graph to read all labels.

Two illustrative cumulative gas-volume curves. Both reach 40 cm³ and remain there through 120 s. The higher-concentration trial reaches its plateau sooner.Two illustrative cumulative gas-volume curves. Both reach 40 cm³ and remain there through 120 s. The higher-concentration trial reaches its plateau sooner.
Constructed data: equal marble portions, acid in excess in both trials, fixed acid volume, temperature and particle size. Higher acid concentration gives a greater initial rate; both reach the same final gas volume.
Open full-size graph
View figure data
Values for Acid concentration and gas-production rate
Time (s)Lower concentrationHigher concentration
000
10612
201222
301829
402434
502937
603339
703640
803840
904040
1204040

These constructed curves compare equal marble portions with acid at different concentrations. Acid is in excess in both trials; marble mass and particle size, acid volume, temperature and gas-collection conditions are held fixed. The more concentrated acid gives a greater initial rate, but the same marble amount gives the same final gas volume. Changing concentration does not always preserve final amount: check which reactant limits the reaction.

B. Pressure (gases)

For a fixed amount of reacting gas at constant temperature, compressing it into a smaller volume raises pressure and usually increases the rate in the collision model because:

  • gas particles are forced closer together (same number of particles in a smaller volume),
  • so there are more collisions per unit time,
  • so there are more frequent effective collisions per unit time.
Industry link (don’t overclaim)

In the Haber process, higher pressure increases rate because gas collisions become more frequent. If supplied data also show a yield change, describe that as a separate trend rather than treating rate and yield as the same quantity. See:

Haber Process

and

Reversible Reactions

.

C. Surface area (solids)

For reactions involving a solid, the syllabus factor is particle size; the collision-theory explanation uses the resulting change in total surface area.

For the same mass of solid, decreasing particle size (for example, powdering it) increases rate because:

  • total surface area increases,
  • more solid particles are exposed to the other reactant,
  • so there are more collisions at the surface per unit time,
  • so there are more frequent effective collisions per unit time.

Compare equal masses of large chips and powder while keeping acid concentration and temperature fixed.

t = 0 s

0.20 g of marble as large chips in 20 cm³ of 1.00 mol/dm³ hydrochloric acid at 25 °C. After 0 s the gas syringe reads 0 cm³.

Volume of gas
0 cm³
Rate at the tangent
— cm³/s
Reaction
mol/dm³
g
Marble pieces
°C

Try this

0 of 4 done
  1. During a run, drag the tangent back to the start of the curve to find the initial rate. (not done yet)

  2. Use two different acid concentrations, with the marble used up both times. (not done yet)

  3. Compare large chips with powder of the same mass. (not done yet)

  4. Decompose H₂O₂ with no MnO₂, then with some MnO₂. (not done yet)

Your readings

#t / sV / cm³Remove
No readings yet. Set up a measurement, then record it.
Keyword trap

Write “larger surface area” and “more collisions at the surface per unit time”. Writing only “smaller particles” is a half-answer.

The same solid, more exposed surfaceA cube of edge length 2a has volume 8a cubed and surface area 24a squared. Eight separated cubes of edge length a have the same total volume, 8a cubed, but total surface area 48a squared. The newly exposed cut faces allow more collisions at the solid surface.One large pieceEight separated piecesEdge length 2aEach edge length aSurface area: 24a²Total surface area: 48a²Volume: 8a³Total volume: 8a³
Ideal cube model: divide one cube into eight equal cubes and separate them so every face is exposed. Solid volume and mass stay the same, while the total exposed surface area doubles. Actual marble pieces are irregular.

In this ideal model, one cube of edge 2a has six faces with total area 6(2a)² = 24a². Eight separate cubes of edge a expose 8 × 6a² = 48a². Their combined volume is still 8a³, so the same solid has twice the exposed surface. The new cut faces matter only when the other reactant can reach them; pieces pressed tightly together do not expose every face.

D. Temperature

For the reactions described by this model, increasing temperature usually increases rate because:

  • particles have more kinetic energy (energy of motion) and move faster,
  • so there are more collisions per unit time, and
  • a larger proportion of particles have energy ≥ Eₐ, so a larger proportion of collisions are effective,
  • so there are more frequent effective collisions per unit time.
Explain both temperature effects

Particles move faster and collide more frequently. A larger fraction of collisions also has enough energy to overcome the barrier. Temperature does not lower Eₐ. Enzyme-catalysed reactions can behave differently if heat damages the enzyme; see Catalysts and Enzymes.

E. Catalysts

Catalysts change the reaction pathway rather than reactant concentration, particle size or temperature. Continue with Catalysts and Enzymes for lower activation energy, industrial examples and biological catalysts.

4. Common Mistakes

  • Writing “rate increases because concentration/pressure is higher” with no particle explanation.
  • Treating total gas pressure as sufficient evidence: check that the concentration of reacting gas particles has increased.
  • Using “particle size” without linking it to surface area and collisions at the surface.
  • Explaining temperature using only “more collisions” and forgetting “larger proportion have energy ≥ Eₐ”.
  • Saying “a catalyst is used up” or “a catalyst gives particles energy” (both false).
  • Confusing “faster rate” with “more products”. Rate describes how quickly change occurs; any yield conclusion must come from the reaction information or supplied data.

5. Exam Tips

Explain what changes, then why rate changes

Start with the changed condition. Connect it to particle spacing, exposed solid surface, or particle energy. State the effect on collision frequency and, for temperature, on the fraction of effective collisions. A list of memorised phrases is not a causal explanation.

  • In a fair test, change the intended factor and hold the others fixed. For a concentration comparison, use different concentrations but the same acid volume, marble mass and particle size, temperature and apparatus.
  • For temperature, distinguish greater particle energy from a changed activation-energy barrier.

6. Worked Examples

Modelled example 1

Pressure (gases only)

Core

Problem

A fixed mixture of N₂(g) and H₂(g) is compressed into a smaller volume at constant temperature. Explain why its reaction rate increases in the collision model.
Study the worked solution
  1. State the particle change

    Method

    Bring the gas particles closer together.

    Reason

    The stated compression puts the same number of gas particles into a smaller volume at constant temperature.

    Working

    More reacting particles per unit volume.
  2. Infer the collision change

    Method

    Increase collisions per unit time.

    Reason

    Closer gas particles encounter one another more frequently.

    Working

    Higher collision frequency.
  3. Conclude with effective collisions

    Method

    State that effective collisions occur more frequently.

    Reason

    A greater number of collisions per second gives more successful collisions per second under otherwise unchanged conditions.

    Working

    More frequent effective collisions per unit time, so rate increases.

Guided practice 2

Surface area (marble + acid)

About 5 min

Problem

Equal masses of large marble chips and powdered CaCO₃(s) react with identical dilute HCl(aq) portions. Explain why the powder reacts faster.

Complete the solid-interface chain

Total surface area
Exposed CaCO3 particles
Surface collisions per unit time

Hints

Hint 1: particle size to area
Smaller particles increase total surface area without changing the marble mass.
Hint 2: interface
Acid particles react only where they can reach exposed marble particles.
View solution step by step
  1. Translate particle size to surface area

    Method

    Give powder the larger total surface area.

    Reason

    Dividing the same mass into smaller particles exposes more solid.

    Working

    More CaCO₃ particles are exposed.
  2. Translate area to rate

    Method

    Increase collisions at the surface per unit time.

    Reason

    More exposed sites allow more frequent effective acid–marble collisions.

    Working

    More frequent effective collisions per unit time, so powder reacts faster.

Common misconception 3

Concentration vs volume (spot the mistake)

Find and correct the mistake

Learner claim

A student says, “Using 50 cm³ of acid instead of 25 cm³ makes the reaction faster because concentration is higher.” Explain the error and state how to test a concentration effect.

Separate amount of solution from particles per volume

Doubling volume alone
Valid concentration change

View solution step by step
  1. Identify the variable error

    Method

    Reject volume as proof of higher concentration.

    Reason

    Concentration is the number of solute particles per unit volume, not the total volume present.

    Working

    50 cm³ of a given solution has the same concentration as 25 cm³ of that solution.
  2. State the correct concentration mechanism

    Method

    Use acid with more reactant particles per unit volume.

    Reason

    Closer, more numerous acid particles collide with the other reactant more frequently.

    Working

    Higher concentration → more frequent effective collisions per unit time → faster rate.

Examiner practice 4

Temperature (full marks)

4 marks

Examination question

Explain, using collision theory, why increasing temperature increases the rate of reaction. [4 marks]

Write the complete causal chain

View solution step by step
  1. Kinetic energy and speed

    1 mark

    Method

    State that particles gain kinetic energy and move faster.

    Reason

    Temperature measures the average kinetic energy of the particle population.

    Working

    Higher temperature → faster particle motion.
  2. Collision frequency

    1 mark

    Method

    Increase collisions per unit time.

    Reason

    Faster-moving particles meet more often.

    Working

    Collision frequency increases.
  3. Activation threshold

    1 mark

    Method

    Increase the proportion with energy at least Eₐ.

    Reason

    A larger fraction of collisions can overcome the activation-energy barrier.

    Working

    Larger proportion with energy ≥ Eₐ.
  4. Rate conclusion

    1 mark

    Working

    More frequent effective collisions per unit time, so rate increases.

Catalyst: what changes and what stays the same

This exercise now belongs with the pathway explanation: Catalyst: what changes and what stays the same.

7. Mind Stretchers

Mind stretcher 1: Same concentration, different ratesExtension

Question: Equal masses of large marble chips and marble powder react with identical acid portions at the same concentration and temperature. Acid is in excess in both trials. Predict the initial gas-production rates and the final gas volumes, and explain both comparisons.

Show Answer

Powder has a larger total exposed surface area, so acid particles collide with the marble surface more frequently. Its initial gas-production rate is greater. Both trials have the same final gas volume because the same marble amount is completely used up with acid in excess. Initial rate and final amount answer different questions.

Mind stretcher 2: Choose the correct explanation sentenceExtension

Question: A student adds an inert gas to a reacting gas mixture without changing the vessel volume or temperature. Total pressure increases, but the amounts of reacting gases stay the same. Does the usual compression explanation predict a greater reaction rate? Explain.

Show Answer

No. The same numbers of reacting particles still occupy the same volume, so their concentrations have not increased. Adding inert gas raises total pressure without compressing the reactants. At the same temperature, the usual collision explanation therefore gives no rate increase. Compare reacting-particle density, not total pressure alone.

8. Practise and check

Practise this lesson

Use the topic check to practise rate explanations and fair-test design. Continue with Catalysts and Enzymes for the pathway mechanism.

Practise and check reaction rates
Syllabus and review details

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