Representations and Nomenclature (A Level Organic)
Move between formula types and name the required classes of organic compound.
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Organic marks are often lost before the chemistry starts: misreading skeletal formulae, miscounting carbons, and naming/numbering errors. This lesson makes those rules automatic so you can decode structures quickly and write exam-safe names.
This topic gets cleaner if you cross-check Organic Mechanisms: Curly Arrows, Electrophiles, Nucleophiles while navigating from the Organic Chemistry hub.
Definitions (Must Know)
A. Structural (displayed) formula
A displayed formula shows all atoms and all bonds explicitly.
B. Skeletal formula
A skeletal formula is a line-angle drawing where:
- each line end / vertex represents a carbon atom,
- hydrogen atoms on carbon are omitted, and
- heteroatoms (e.g. O, N, halogens) are shown explicitly with their attached hydrogens.
C. Functional group
A functional group is the atom/group of atoms responsible for a molecule’s characteristic reactions (e.g. -OH in alcohols).
D. Homologous series
A homologous series is a family of organic compounds with the same functional group and general formula, where successive members differ by -CH₂-.
Key Ideas (What Earns Marks)
- Every carbon must have 4 bonds (count double bond as 2, triple as 3).
- Identify the longest carbon chain that includes the functional group.
- Number the chain so the functional group gets the lowest possible number.
- Use suffixes for the highest-priority functional group (e.g.
-ol,-al,-one,-oic acid) and prefixes for substituents (e.g.chloro-,methyl-).
- Every line end/vertex is a carbon. - Add enough H to each carbon to make 4 bonds. - Heteroatoms (O, N, halogens) are always shown explicitly.
Detailed Explanations
A. Common representations (what the question might show)
- Empirical formula: simplest whole-number ratio of atoms.
- Molecular formula: actual number of each type of atom (e.g. C₄H₁₀). No connectivity is shown.
- Structural formula: shows the order in which atoms are joined, usually in a compact form such as CH₃CH₂OH.
- Displayed formula: all bonds shown.
- Skeletal formula: fastest for larger molecules; you must infer omitted hydrogens correctly.
- Three-dimensional formula: a solid wedge shows a bond coming out of the plane; a dashed wedge shows one going behind it.
B. Workflow: reading a skeletal structure correctly
- Count the carbon atoms (each vertex/line end is one carbon).
- Identify any heteroatoms (they are drawn explicitly).
- For each carbon, count the bonds already shown; add H atoms until that carbon has 4 bonds.
Because carbon forms 4 covalent bonds, therefore any “missing bonds” in a skeletal structure are completed by hydrogens.
Mini example:
- A 4-vertex zig-zag chain with no heteroatoms is a 4-carbon alkane → C₄H₁₀ (butane).
C. Functional groups (core set)
| Functional group | Example | Notes |
|---|---|---|
| Alkane | CH₃CH₃ | no functional group; only single C–C bonds |
| Alkene | CH₂ = CH₂ | contains C=C |
| Halogenoalkane | CH₃CH₂Cl | C–X where X = F/Cl/Br/I |
| Alcohol | CH₃CH₂OH | contains –OH |
| Aldehyde | CH₃CHO | terminal -CHO |
| Ketone | CH₃COCH₃ | internal C = O |
| Carboxylic acid | CH₃COOH | contains -COOH |
| Amine | CH₃NH₂ | contains –NH2 (or substituted) |
| Arene | C₆H₆ | contains a benzene ring |
| Phenol | C₆H₅OH | –OH attached directly to a benzene ring |
| Ester | CH₃COOCH₃ | contains -COO⁻ |
| Acyl chloride | CH₃COCl | contains -COCl |
| Amide | CH₃CONH₂ | contains -CONH₂ or a substituted amide group |
| Nitrile | CH₃CN | contains -C#N |
| Amino acid | H₂NCH₂COOH | contains both amino and carboxyl groups |
D. Workflow: naming (IUPAC basics)
- Choose the longest chain containing the functional group.
- Number to give the functional group the lowest locant.
- Name substituents with locants, list alphabetically (ignore di-/tri- for ordering).
- Apply the suffix and functional group locant (where needed).
Mini example:
- CH₃CH(Cl)CH₃ has a 3-carbon chain (propane) with Cl on carbon 2 → 2-chloropropane.
E. Local shape, hybridisation and bonds
| Carbon centre | Hybridisation | Local shape | Approximate angle | Bonding feature |
|---|---|---|---|---|
| four electron regions | sp³ | tetrahedral | 109.5° | four σ bonds |
| carbon in C=C or C=O | sp² | trigonal planar | 120° | three σ regions and one π bond |
| carbon in C≡C or C≡N | sp | linear | 180° | two σ regions and two π bonds |
A single bond is one σ bond. A double bond is one σ plus one π bond; a triple bond is one σ plus two π bonds. Use the local carbon centre, not the shape of the whole molecule, when stating hybridisation and bond angle.
Worked Examples
Modelled example 1
Name a Straight-Chain Alcohol
Problem
Study the worked solution
Choose the parent
Method
Count three carbons in the longest chain containing the alcohol group.
Reason
The principal functional group must belong to the parent chain.
Working
Three-carbon parent: propane.Number from the correct end
Method
Number from the end nearest OH, placing it on carbon 1.
Reason
The principal functional group receives the lowest possible locant.
Working
OH locant: 1.Build the name
Method
Replace the final “e” of propane with the alcohol suffix and retain the locant.
Reason
The suffix identifies the functional group and the locant distinguishes its position.
Working
Name: propan-1-ol.
Common misconception 2
Locate Chlorine on the Parent Chain
Learner claim
Try this before viewing the solution
View solution step by step
Trace the carbon chain
Method
Label the three connected carbons 1–2–3.Reason
Locants describe connectivity, not where a symbol happens to appear on the page.Working
CH₃-CH(Cl)-CH₃: Cl is attached to the middle carbon.State the corrected name
Method
Name the compound 2-chloropropane.Reason
Numbering from either end places chlorine on carbon 2.Working
Correct name: 2-chloropropane.
Challenge 3
Draw 2-Methylpropane from Its Name
Representation transfer
Try this before viewing the solution
Hints
Hint 1: build the parent
Hint 2: add the substituent
View solution step by step
Construct the named skeleton
Method
Attach a methyl group to carbon 2 of propane.Reason
The parent and substituent parts of the name account for all four carbons.Working
CH₃-CH(CH₃)-CH₃.Audit the central carbon
Method
Confirm that the central carbon has four single bonds: three to carbon and one to hydrogen.Reason
Carbon valency distinguishes the intended branched structure from an incomplete drawing.Working
Unambiguous structural formula: (CH₃)₃CH.
Common Mistakes
- Miscounting carbons in skeletal structures (each vertex counts).
- Forgetting that heteroatoms must be shown explicitly (you can’t “assume an oxygen”).
- Numbering from the wrong end, giving higher locants than necessary.
- Treating a displayed formula like a skeletal formula (displayed must show every atom and bond).
Use the Organic Chemistry topic check to practise and check your understanding.
Exam Tips
- If the question shows a skeletal structure, rewrite it mentally as a displayed formula before deciding the name.
- When asked to “draw a displayed formula”, show every bond and every atom label.
- If a name includes a locant (e.g.
butan-2-ol), the position number is a mark: do not omit it.
Mind Stretchers
Mind stretcher 1Extension
A skeletal structure has 5 vertices in a straight chain, with an -OH shown on the second vertex from one end. What is the IUPAC name?
Show Hint
Count the carbon vertices first, then number from the end nearest the principal group.
Show Answer
Mark scheme:
- 5-carbon chain = pentane.
- Number from the end that gives -OH the lowest locant → -OH on carbon 2.
- Name: pentan-2-ol.
Mind stretcher 2: Resolving an ambiguous condensed formulaExtension
Question. A student writes C₃H₆O and calls it propanone. Explain why the molecular formula alone does not prove that name, and give one alternative structure.
Show Hint
A molecular formula gives atom counts but not connectivity or functional-group position.
Show Answer
C₃H₆O does not show how the atoms are connected, so it can represent more than one constitutional isomer. Propanal, CH₃CH₂CHO, is one alternative to propanone, CH₃COCH₃.
Syllabus and review details
- GCE A-Level H2 Chemistry 9476-2027 · 9476-2027
9476 (2027), complete syllabus
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