The Reactivity Series of Metals
Use water, steam, dilute-acid and displacement observations to compare metals and explain electron transfer.
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The reactivity series ranks metals by how readily they lose electrons and form positive ions. It helps you predict reactions and explain observations. Start with the order, then use each experiment to make one comparison.
1. Definition
A. Reactivity series
A more reactive metal has a greater tendency to form positive ions. For example, magnesium loses electrons more readily than copper. This is a chemical tendency, not a claim that every magnesium sample reacts faster in every experiment.
2. Key Ideas
- Learn the required order below; hydrogen is a reference, not a metal.
- Compare reactions with water, steam and dilute hydrochloric acid under controlled conditions.
- A more reactive metal can displace a less reactive metal from its aqueous salt solution.
- Turn each displacement result into an inequality before combining results.
3. Detailed Explanations
A. The required K324 / 6092 order
| Position | Element | Symbol |
|---|---|---|
| most reactive | potassium | K |
| ↓ | sodium | Na |
| ↓ | calcium | Ca |
| ↓ | magnesium | Mg |
| ↓ | zinc | Zn |
| ↓ | iron | Fe |
| ↓ | lead | Pb |
| reference | hydrogen | H |
| ↓ | copper | Cu |
| least reactive | silver | Ag |
Hydrogen is included to help predict reactions with dilute acids. Carbon and aluminium are useful in other contexts, but are not additional entries to memorise in this required order.
B. Deducing reactivity from evidence
If X displaces Y from an aqueous solution containing Y ions, X > Y. If Y displaces Z, Y > Z. Combining both results gives X > Y > Z. Here, > means “more reactive than”.
A single result X > Y tells you nothing about where an untested Z belongs. Distinguish an observed displacement from a colour change caused only by dilution.
C. Reactions with water, steam and dilute acid
The reaction depends on both the metal and the conditions. These observations are from controlled demonstrations; the very reactive metals require appropriate teacher handling.
| Metals | With water or steam | With dilute hydrochloric acid |
|---|---|---|
| potassium, sodium, calcium | react with cold water; generally less vigorous from potassium to sodium to calcium | water observations are used to compare these very reactive metals |
| magnesium | very slow with cold water; more readily with steam | releases hydrogen |
| zinc, iron | no reaction with cold water; react with steam when heated | release hydrogen; zinc generally reacts faster under comparable conditions |
| lead | no reaction with cold water; little useful reaction with steam | slow reaction can stop as an insoluble lead(II) chloride coating forms |
| copper, silver | no reaction with water or steam | do not release hydrogen |
With cold water, potassium, sodium and calcium form a metal hydroxide and hydrogen. For example:
Ca(s) + 2H₂O(l) → Ca(OH)₂(aq) + H₂(g)
With steam, magnesium forms a metal oxide and hydrogen:
Mg(s) + H₂O(g) → MgO(s) + H₂(g)
Do not use the hydroxide equation for the steam reaction. Hot iron reacts with steam to form Fe₃O₄ and hydrogen, rather than iron hydroxide.
Metals above hydrogen can displace hydrogen ions from dilute hydrochloric acid:
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
Magnesium loses electrons; hydrogen ions gain them to form hydrogen gas. Copper and silver lie below hydrogen and do not release hydrogen from this acid. This rule is for dilute hydrochloric acid: it is not a rule for every acid.
Control temperature, acid concentration, exposed metal surface area and the amounts used. Equal masses alone do not guarantee equal surface areas. A surface coating can slow a reaction: lead reacting slowly does not move it below hydrogen in the series.
D. Metal displacement
Magnesium in copper(II) sulfate solution forms magnesium ions while copper ions become copper metal. The blue solution becomes paler and a reddish-brown copper deposit forms.
Mg(s) + Cu²⁺(aq) → Mg²⁺(aq) + Cu(s)
Mg → Mg²⁺ + 2e⁻ Cu²⁺ + 2e⁻ → Cu
Magnesium is oxidised; copper ions are reduced. Sulfate ions do not change and are omitted from the ionic equation. Copper metal cannot displace magnesium ions: that would require the less reactive metal to take the more reactive metal’s place.
For aqueous displacement comparisons, use suitable metals such as magnesium, zinc, iron and copper. Potassium and sodium react with the water itself, so putting them into a salt solution is not a clean test of metal-ion displacement.
E. Reduction of metal oxides
The next lesson explains oxide reduction and extraction. Keep this separate from hydrogen’s position in the dilute-acid comparison.
F. Thermal stability of metal carbonates
Continue with what happens when carbonates are heated.
G. Obtaining metals from ores
Learn how reactivity affects the choice of extraction method.
H. Rusting and protection of iron
Use the same series to understand why zinc and magnesium protect iron.
4. Common Mistakes
- Hydrogen is a reference, not a metal.
- The displacing metal loses electrons; the displaced metal ions gain them.
- Faster bubbling is useful evidence only when the conditions are controlled.
- No reaction with cold water does not mean no reaction with steam or dilute acid.
5. Exam Tips
State the observation, convert it into a comparison, then give the supported order. Check that your order predicts every displacement in the question.
6. Worked Examples
Modelled example 1
Use the required order
Problem
Arrange magnesium, silver, lead and zinc from most to least reactive.
Study the worked solution
Locate each metal in the required series
Method
Find magnesium, zinc, lead and silver without inserting hydrogen or carbon into the answer.
Reason
The comparison contains metals only and uses their relative positions in the reactivity series.
Working
Required order includes Mg above Zn above Pb above Ag.
Read from most to least reactive
Method
Write the selected metals from higher to lower position.
Reason
A higher position means a greater tendency to lose electrons and form positive ions.
Working
magnesium > zinc > lead > silver.
Guided practice 2
Deduce from displacement
Problem
Metal P displaces Q from QSO₄(aq), while Q displaces R from RSO₄(aq). Deduce the reactivity order.
Convert each observation into an inequality
Hints
Hint 1: use the displacement rule
A more reactive metal forms ions and displaces a less reactive metal from its salt solution.
Hint 2: link through Q
Write P > Q and Q > R on separate lines before joining them.
View solution step by step
Interpret the first result
Method
Place P above Q.Reason
P can displace Q ions only if P is more reactive.Working
P > Q.Interpret the second result
Method
Place Q above R.Reason
Q displaces R ions and is therefore more reactive than R.
Working
Q > R.Combine both constraints
Method
Use Q as the common middle metal.Reason
The two observations support one consistent chain.Working
P > Q > R.
Interpret carbonate data is now in the lesson devoted to this application.
Explain a rusting control is now in the lesson devoted to this application.
Interpret extraction evidence is now in the lesson devoted to this application.
7. Mind Stretchers
Try independently: Iron is placed in copper(II) sulfate solution. Predict the observations and write the ionic equation. Then predict what happens when copper is placed in iron(II) sulfate solution.
Show answer and reasoning
Iron lies above copper, so a reddish-brown copper deposit forms and the blue solution changes towards pale green as iron(II) ions form. Fe(s) + Cu²⁺(aq) → Fe²⁺(aq) + Cu(s). Copper cannot displace iron ions, so there is no displacement in the reverse test.
Combine two evidence types in the extraction lesson.
Explain a damaged zinc coating in the rusting lesson.
8. Quiz
Use the Periodic Table topic check to practise and check your understanding.
Syllabus and review details
- SEC G3 Pure Chemistry 2027 · 2027
Content structure and subject content, PDF pages 9–24
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