Mole quantities lab
Weigh out magnesium, measure acid and gas volumes, and count the particles in moles to find the limiting reactant, gas volumes at r.t.p. and percentage yield.
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Learning objectives
- interpret chemical equations with state symbols
- perform calculations involving the relationship between the amount of substances in moles, mass and molar mass (calculations of stoichiometric reacting masses and volumes of gases are not required).
- define the term mole in terms of the Avogadro constant
- calculate stoichiometric reacting masses and volumes of gases (one mole of gas occupies 24 dm3 at room temperature and pressure); calculations involving the idea of limiting reactants may be set (knowledge of the gas laws and the calculations of gaseous volumes at different temperatures and pressures are not required)
- apply the concept of solution concentration (in mol/dm3 or g/dm3) to process the results of volumetric experiments (e.g. titration) and to solve simple problems. (appropriate guidance will be provided where unfamiliar reactions such as redox are involved. Calculations on % yield and % purity are not required.)
- apply the concept of solution concentration (in mol/dm3 or g/dm3) to process the results of volumetric experiments (e.g. titration) and to solve simple problems (appropriate guidance will be provided where unfamiliar reactions are involved)
- calculate % yield and % purity.
- perform calculations, including use of the mole concept, involving: — reacting masses (from formulae and equations)
- perform calculations, including use of the mole concept, involving: — volumes of gases (e.g. in the burning of hydrocarbons)
- perform calculations, including use of the mole concept, involving: — volumes and concentrations of solutions [when performing calculations, candidates’ answers should reflect the number of significant figures given or asked for in the question]
- deduce stoichiometric relationships from calculations such as those in (i)
- Mole and Avogadro Constant
- Reacting Masses and Limiting Reagent
- Gas Calculations (pV = nRT)
- Solution Concentration and Dilution
- Titration Calculations
0.096 g of magnesium and 20 cm³ of 0.6 mol/dm³ hydrochloric acid. Amounts now: Mg 0.00395 mol, HCl 0.0120 mol, MgCl₂ 0 mol, H₂ 0 mol.
- n(Mg)
- 0.00395 mol
- n(HCl)
- 0.0120 mol
- n(H2)
- 0.00395 mol
- n(O2)
- 0.0120 mol
- n(CaCO3)
- 0.00395 mol
- Volume of H2
- 0 cm³
- Gas left
- — cm³
- Theoretical mass of CO2
- 0.88 g
- Percentage yield of CO2
- — %
- Limiting reactant
- —
Try this
0 of 4 doneChoose magnesium and acid that react with nothing left over, then start. (not done yet)
The equation needs 2 mol of HCl for every 1 mol of Mg. With exactly that ratio, both run out together.
Run Mg + HCl once with the magnesium used up and once with the acid used up. (not done yet)
The reactant that runs out first is the limiting reactant. It alone sets how much H₂ forms; extra of the other reactant is left over.
Mix hydrogen and oxygen so that no gas is left after the spark. (not done yet)
At the same temperature and pressure, equal volumes of gases hold equal numbers of molecules. So the 2 : 1 mole ratio is also a 2 : 1 volume ratio.
Weigh the crucible part-way through heating, then again once its mass stops changing. (not done yet)
Heating to constant mass makes sure all the CaCO₃ has decomposed. Percentage yield = actual mass of CO₂ lost ÷ theoretical mass × 100.
Your readings
| # | t / min | m / g | Remove |
|---|---|---|---|
| No readings yet. Set up a measurement, then record it. | |||