Transition Elements

Learn the typical K324 / 6092 properties of transition elements: high melting points and densities, variable oxidation states, coloured compounds and catalysts.

  • SEC G3 Pure Chemistry 2027
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Iron can form both Fe²⁺ and Fe³⁺ ions. Copper(II) sulfate makes a blue solution, while some transition metals and their compounds speed up reactions. These observations show different properties: learn to connect each piece of evidence to the claim it supports.

Where to find typical transition elements

Transition elements such as iron and copper are metals in the central block of the Periodic Table, between Groups 2 and 13. This course compares their typical properties. A position in the central block is a useful guide, but it does not mean that every element there shows every property below.

Physical properties: compare with Group 1 metals

Typical transition metals conduct heat and electricity and are malleable and ductile. Compared with lithium, sodium and potassium, they are generally harder, denser and higher-melting.

PropertyGroup 1 examples: lithium, sodium, potassiumTypical transition elements
Melting pointRelatively low for metalsGenerally higher
DensityLow; all three float on waterGenerally higher
HardnessSoftGenerally harder

High melting point and high density are separate physical properties. These are general comparisons, not guarantees about every metal or alloy.

The same element can have different oxidation states

Iron forms two common ions:

  • Fe²⁺: iron(II), oxidation state + 2;
  • Fe³⁺: iron(III), oxidation state + 3.

The two charges demonstrate variable oxidation states. Both ions are iron: they have the same proton number. The Roman numeral records the oxidation state, not a number of atoms.

For a monatomic ion, oxidation state equals the ion charge. For an atom within a compound or a polyatomic ion, use the separate oxidation-state rules. Do not read an oxidation state as a total electron count.

Coloured compounds: name the substance and its state

Many transition-metal compounds are coloured. Familiar aqueous examples include:

Aqueous substanceTypical colour
Copper(II) sulfate, CuSO₄(aq)Blue
Iron(II) sulfate, FeSO₄(aq)Pale green
Iron(III) chloride, FeCl₃(aq)Yellow-brown
Potassium manganate(VII), KMnO₄(aq)Purple

Colour depends on the particular compound and conditions, not just the name of the metal. Anhydrous copper(II) sulfate is white, while hydrated copper(II) sulfate is blue. A white compound therefore does not rule out a transition element.

Potassium manganate(VII) contains potassium, a Group 1 metal, but its purple colour comes from the manganate(VII) ion containing manganese, a transition element. This is why “all Group 1 salts are white” is not a reliable rule. Sodium chloride and potassium chloride are familiar white salts whose solutions are colourless.

Catalysts: look for rate and recovery evidence

Transition elements and their compounds often act as catalysts. A catalyst increases reaction rate and is not consumed overall. For example, manganese(IV) oxide speeds up hydrogen peroxide decomposition and remains after the reaction.

Compare a reaction with and without the possible catalyst under otherwise comparable conditions. A faster reaction and recovery of the substance support catalyst behaviour. They do not prove by themselves that the substance is a transition-metal compound: other kinds of substance can also be catalysts.

For a reversible reaction at the same temperature, a catalyst does not change the equilibrium yield. It helps the reaction reach equilibrium faster. More product collected after a short fixed time can reflect a faster reaction rather than a changed equilibrium. See reversible reactions for that distinction.

Match evidence to the right property

Evidence suppliedSupported claim
The same element forms M²⁺ and M³⁺Variable oxidation states
A named aqueous compound is blueThat compound is coloured
A substance increases rate and is recovered unchangedCatalyst behaviour in that reaction
A metal melts at a much higher temperature than sodiumHigher melting point than sodium

One observation does not establish all the typical properties. In particular, colour alone is not a conclusive identification of an ion, and a compound need not catalyse every reaction.

State the property, then give its evidence

“Variable oxidation states, shown by Fe²⁺ and Fe³⁺” is stronger than writing two ion formulae without an explanation. For a catalyst, state both increases rate and not consumed overall. Keep high density and high melting point distinct if a question asks for physical properties.

Worked examples

Modelled example 1

Connect properties to examples

Core

Problem

Describe two typical physical properties and three typical chemical behaviours of transition elements, using an example where helpful.

Study the worked solution
  1. Give the physical comparison

    Method

    Compare density and melting point with Group 1 metals.

    Reason

    The syllabus treats transition elements as generally denser and higher-melting than Group 1 metals.

    Working

    Generally high density and high melting point.
  2. Give the ion and compound properties

    Method

    State variable oxidation states and coloured compounds.

    Reason

    Many transition elements form ions with different charges and compounds with characteristic colours.

    Working

    Examples: Fe²⁺/Fe³⁺; blue CuSO₄(aq).
  3. Give the reaction-role property

    Method

    State that transition elements and their compounds often act as catalysts.

    Reason

    They can increase reaction rate without being consumed overall.

    Working

    Physical: high density and high melting point. Chemical: variable oxidation states, coloured compounds and catalyst behaviour.

Guided practice 2

Variable oxidation states (example)

About 5 min

Problem

Give one transition element that forms ions with different charges, write both ions and name them.

Use charges as the evidence

Suitable element
Ion pair

Hints

Hint 1: choose a course example

Iron is a suitable named example.

Hint 2: show the distinction

The charge symbols must differ; names use Roman numerals to match them.

View solution step by step
  1. Choose one element

    Method

    Select iron.

    Reason

    Iron is a transition element with two common ion charges in this course.

    Working

    Element: Fe.
  2. Write and name both ions

    Method

    Give the charge and corresponding name for each ion.

    Reason

    Different charges of the same element are the evidence for variable oxidation states.

    Working

    Fe²⁺, iron(II), and Fe³⁺, iron(III).

Common misconception 3

Identify catalyst evidence

Find and correct the mistake

Learner response

Compound X increases reaction rate and is recovered unchanged. A student says: “X is a catalyst because it changes the equilibrium yield and is used up slowly.” Correct both errors and name the transition-element property demonstrated.

Separate rate from yield and consumption

Catalyst effect
At reaction end

View solution step by step
  1. Correct the process effect

    Method

    Replace “changes equilibrium yield” with “increases reaction rate.”

    Reason

    A catalyst changes how quickly equilibrium or completion is reached, not the equilibrium position.

    Working

    Observed evidence: faster reaction.
  2. Correct the consumption claim

    Method

    State that X is not used up overall.

    Reason

    Recovery unchanged is direct evidence of catalyst behaviour.

    Working

    X before reaction = X recovered after reaction.

  3. Name the property

    Working

    X demonstrates the tendency of transition-element compounds to act as catalysts.

Examiner practice 4

Colour identification

2 marks

Examination question

A solution is blue. Name a common transition-metal ion that could cause the colour and give one corresponding aqueous compound. [2 marks]

Name the species, not only the colour

View solution step by step
  1. Name the ion

    1 mark

    Method

    Identify copper(II) ions.

    Reason

    Aqueous Cu²⁺ is a familiar transition-metal species associated with a blue solution.

    Working

    Ion: Cu²⁺.
  2. Give a compound example

    1 mark

    Method

    Name aqueous copper(II) sulfate.

    Reason

    It supplies copper(II) ions in solution.

    Working

    Example: CuSO₄(aq).

Challenge 5

Use supplied evidence

Minimal support

Evidence-mapping transfer

An unfamiliar metal M has a high melting point, forms both M²⁺ and M³⁺ ions, and makes coloured compounds. State exactly which three typical transition-element properties these data support, without claiming a fourth.

Map each observation once

Two ion charges support
Not supported by these data

Hints

Hint 1: match rather than recall

Use each observation as direct evidence for one property.

Hint 2: police the extra claim

Catalyst behaviour requires evidence that a substance speeds a reaction without being used up.

View solution step by step
  1. Use the thermal evidence

    Method

    Record the high melting point.

    Reason

    This is directly stated and is a typical transition-element physical property.

    Working

    Supported property 1: high melting point.
  2. Use the charge evidence

    Method

    Compare M²⁺ with M³⁺.

    Reason

    Two ion charges show variable oxidation states.

    Working

    Supported property 2: variable oxidation states.
  3. Use colour and bound the claim

    Method

    Record coloured-compound formation and stop there.

    Reason

    The data give no evidence about reaction rate or catalyst recovery.

    Working

    Supported property 3: coloured compounds; catalyst behaviour is not established.

Try these independently

Mind stretcher 1: Match evidence to propertiesExtension

Question: A metal forms both M²⁺ and M³⁺ ions, and one of its compounds speeds up a reaction without being consumed overall. Which two typical properties does this evidence support?

Show Answer

The two ion charges show variable oxidation states. Speeding up a reaction without being consumed overall shows catalyst behaviour.

Mind stretcher 2: Evidence-based comparisonExtension

Question: A metal forms a white compound that does not speed up the reaction tested. Do these observations prove that the metal is not a transition element? Explain.

Show Answer

No. Typical does not mean universal: transition elements can form white compounds, and not every compound catalyses every reaction. These observations do not establish the metal’s identity. Further evidence, such as its position and behaviour across different compounds, is needed.

Practise and check

Practise and check

Practise matching physical and chemical properties to supplied evidence, including oxidation states, colours and catalyst behaviour.

Open the Periodic Table topic check
Syllabus and review details

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