Electrochemistry

Study H2 Chemistry electrode potentials, cells and electrolysis, balancing redox equations and relating cell voltage to reaction feasibility.

  • GCE A-Level H2 Chemistry 2027
  • 6 lessons

Before you begin

This topic measures how strongly redox couples gain electrons, and uses those electrode potentials to predict which reactions are feasible, how much energy they release and what electrolysis produces. It starts with the standard hydrogen electrode, builds cells and overall equations from half-equations, links cell potentials to Gibbs energy, then applies the ideas to electrolysis, batteries and fuel cells.

Be comfortable with: Gibbs energy and feasibility, Le Chatelier’s principle, the mole, gas calculations, and assigning oxidation numbers.

Learning goals
  • Standard Electrode Potentials and the SHE
  • Cell Potentials and Spontaneity
  • Writing Redox Equations from Half-equations
  • ΔG = −nFE
  • Electrolysis Predictions and Faraday’s Law
  • Batteries and Fuel Cells
Syllabus statements covered
  • define the terms: — standard electrode (redox) potential
  • define the terms: — standard cell potential
  • describe the standard hydrogen electrode
  • describe methods used to measure the standard electrode potentials of: — metals or non-metals in contact with their ions in aqueous solution
  • describe methods used to measure the standard electrode potentials of: — ions of the same element in different oxidation states
  • calculate a standard cell potential by combining two standard electrode potentials
  • use standard cell potentials to: — explain/deduce the direction of electron flow from a simple cell
  • use standard cell potentials to: — predict the spontaneity of a reaction
  • understand the limitations in the use of standard cell potentials to predict the spontaneity of a reaction
  • predict qualitatively how the value of an electrode potential varies with the concentration of the aqueous ion
  • describe and explain redox processes in terms of electron transfer and/or of changes in oxidation number (oxidation state)
  • construct redox equations using the relevant half-equations (see also Section 13)
  • state and apply the relationship ∆G⦵ = −nFE⦵ to electrochemical cells, including the calculation of E⦵ for combined half reactions
  • state the relationship, F = Le, between the Faraday constant, the Avogadro constant and the charge on the electron
  • predict the identity of the substance liberated during electrolysis from the state of electrolyte (molten or aqueous), position in the redox series (electrode potential) and concentration
  • calculate: — the quantity of charge passed during electrolysis
  • calculate: — the mass and/or volume of substance liberated during electrolysis
  • explain, in terms of the electrode reactions, the industrial processes of: — the anodising of aluminium
  • explain, in terms of the electrode reactions, the industrial processes of: — the electrolytic purification of copper [technical details are not required]
  • state the possible advantages of developing other types of cell, e.g. the H2/O2 fuel cell and improved batteries (as in electric vehicles) in terms of smaller size, lower mass and higher voltage

Lessons

Work through them in order.

Practise and check

Or choose

Topic reference

Quick reference

Oxidation is always at the anode and reduction always at the cathode. The electrode signs swap between a cell producing a current and electrolysis.
Question evidenceFirst moveEssential check
one half-cell to measureconnect it to the SHE298 K, 1 bar, 1.00 mol dm⁻³; platinum if no solid metal
two electrode potentialsthe more positive couple is reducedE⦵_cell = E⦵_reduction-E⦵_oxidation
a reaction to testkeep its directionpositive means feasible under standard conditions
an overall equation to buildreverse one half-equation, match electronsnever multiply E⦵
Δ G⦵ from a cellΔ G⦵ = -nFE⦵_celln from the balanced equation; answer in J mol⁻¹ first
a combined half-equationadd the Δ G⦵ values, not the potentialsconvert back with the new n
a concentration changeshift the equilibrium Ox + ne⁻ ⇌ Redmore oxidised form makes E more positive
an aqueous electrolytecompare the ions with waterconcentration decides chloride versus oxygen
a current and timeQ = It, then n(e⁻) = Q/Ftime in seconds; ratio from the half-equation

Core knowledge to remember

  • Electrode potentials are reduction potentials measured against the standard hydrogen electrode, E⦵ = 0.00 V, at 298 K, 1 bar and 1.00 mol dm⁻³.
  • A more positive E⦵ means the oxidised form is a stronger oxidising agent.
  • E⦵_cell = E⦵_reduction-E⦵_oxidation; a positive value means feasible under standard conditions, but says nothing about rate.
  • In a cell producing a current, the anode is negative; in electrolysis, the anode is positive. Oxidation is always at the anode.
  • Δ G⦵ = -nFE⦵_cell and F = Le = 9.65 × 10⁴ C mol⁻¹.
  • Increasing the concentration of the oxidised form of a couple makes its electrode potential more positive.
  • In aqueous electrolysis with inert electrodes: reactive metals give hydrogen at the cathode; sulfate gives oxygen at the anode; dilute chloride gives mainly oxygen and concentrated chloride gives chlorine.
  • New cells aim to be smaller, lighter and higher in voltage; the hydrogen–oxygen fuel cell gives 1.23 V and water.

Common mistakes

  • Calling data-booklet values oxidation potentials.
  • Multiplying E⦵ when a half-equation is scaled.
  • Reversing the subtraction for E⦵_cell, or reversing a reaction you were asked to test.
  • Treating a positive cell potential as proof that a reaction is fast.
  • Taking n from an unbalanced half-equation in Δ G⦵ = -nFE⦵, or mixing J and kJ.
  • Adding electrode potentials to find the potential of a combined half-equation.
  • Using minutes in Q = It, or assuming one mole of electrons gives one mole of product.
  • Predicting aqueous electrolysis as if water were absent.
  • Describing anodising or copper purification without the electrode reactions.