Carboxylic Acids and Derivatives
Learn and apply Carboxylic Acids and Derivatives in the published Chemistry course sequence.
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Carboxylic Acids and Derivatives: Orientation
Carboxylic acids and their derivatives are tested by “reactivity + conditions”: predict products and write the right by-products (often HCl or H₂O). This lesson links esterification, acyl chloride reactions, and hydrolysis to the mark-scheme phrases examiners expect.
This topic gets cleaner if you cross-check Organic Mechanisms: Curly Arrows, Electrophiles, Nucleophiles while navigating from the Organic Chemistry hub.
Definitions (Must Know)
A. Carboxylic acid
A carboxylic acid contains the -COOH functional group (e.g. CH₃COOH).
B. Acid derivative (at this level)
Common derivatives you will meet:
- Acyl chlorides: RCOCl
- Esters: RCOOR'
C. Esterification
Esterification is the reaction of a carboxylic acid with an alcohol to form an ester and water (usually acid-catalysed and heated).
D. Hydrolysis
Hydrolysis is bond breaking by reaction with water (often with acid/base and heat), e.g. ester → carboxylic acid (or carboxylate) + alcohol.
Detailed Explanations
A. Formation routes (common syllabus links)
- Oxidation of a primary alcohol (via aldehyde) to a carboxylic acid: CH₃CH₂OH → [O] CH₃CHO → [O] CH₃COOH
- Hydrolysis of nitriles (often via an amide intermediate): R-CN + 2H₂O → [H + /heat] R-COOH + NH₄ +
B. Typical acid reactions (what to write)
- With metals (salt + hydrogen): 2RCOOH + Mg → (RCOO)₂Mg + H₂
- With bases (neutralisation): RCOOH + NaOH → RCOONa + H₂O
- With carbonates (salt + water + carbon dioxide): 2RCOOH + Na₂CO₃ → 2RCOONa + H₂O + CO₂
C. Esterification (condensation)
General: RCOOH + R'OH ⇌ RCOOR' + H₂O
Conditions to quote:
- concentrated H₂SO₄ catalyst
- heat (often reflux)
D. Acyl chlorides (reactivity + key reactions)
1) Hydrolysis
RCOCl + H₂O → RCOOH + HCl
2) With alcohols (ester formation)
RCOCl + R'OH → RCOOR' + HCl
3) With ammonia / amines (amide formation)
RCOCl + 2NH₃ → RCONH₂ + NH₄Cl
Key explanation: Because Cl⁻ is a good leaving group and the carbonyl carbon is strongly electrophilic, therefore acyl chlorides react rapidly with nucleophiles (water, alcohols, ammonia).
E. Hydrolysis of esters
Acid hydrolysis (reversible): RCOOR' + H₂O ⇌ [H + /heat] RCOOH + R'OH
Alkaline hydrolysis (often treated as “complete”): RCOOR' + OH⁻ → RCOO⁻ + R'OH
F. Workflow: choosing the correct products (exam method)
- Identify the carbonyl derivative (acid / acyl chloride / ester).
- Identify the nucleophile: water, alcohol, ammonia/amine, or OH⁻.
- Write products by swapping the leaving group:
- acyl chloride + water → carboxylic acid + HCl
- acyl chloride + alcohol → ester + HCl
- ester + OH⁻ → carboxylate + alcohol
Mini example: CH₃COCl + C₂H₅OH → CH₃COOC₂H₅ + HCl (ethyl ethanoate forms).
G. Further conversions of acids and acyl chlorides
- Convert a carboxylic acid to an acyl chloride using PCl₅: RCOOH + PCl₅ → RCOCl + POCl₃ + HCl.
- Reduce a carboxylic acid to a primary alcohol using LiAlH₄ in dry ether, followed by water.
- An acyl chloride reacts with a primary amine to form an N-substituted amide; a second amine molecule removes the hydrogen chloride formed.
- An acyl chloride reacts with phenol or phenoxide to form a phenyl ester. Benzoyl chloride with phenol gives phenyl benzoate.
H. Why different chlorides hydrolyse at different rates
Acyl chlorides hydrolyse rapidly because the carbonyl carbon is strongly δ + and chloride is a good leaving group. Halogenoalkanes hydrolyse more slowly by nucleophilic substitution, with rate depending on C–X bond strength and structure. Halogenoarenes such as chlorobenzene resist hydrolysis because their C–Cl bond has partial double-bond character and the usual SN1/SN2 routes are unfavourable.
In a comparison question, identify the type of chloride first, then explain electron distribution, bond strength and mechanism. “All contain chlorine” is not a chemical explanation.
Worked Examples
Modelled example 1
Prepare Ethyl Ethanoate
Problem
Study the worked solution
Read the ester name
Method
Match ethyl to ethanol and ethanoate to ethanoic acid.Reason
The alkyl part comes from the alcohol and the carboxylate part from the acid.Working
ethanol + ethanoic acid.State catalyst and heating
Method
Heat under reflux with concentrated sulfuric acid.Reason
The acid catalyses esterification while reflux permits sustained heating.Working
C₂H₅OH + CH₃COOH ⇌ CH₃COOC₂H₅ + H₂O; concentrated H₂SO₄, reflux.
Guided practice 2
Hydrolysis of Ethanoyl Chloride
Problem
Choose both products
Hints
Hint 1: replacement
Hint 2: balance
View solution step by step
Form the carboxylic acid
Method
Replace Cl by OH at the acyl carbon.Reason
Acyl chlorides hydrolyse readily with water.Working
CH₃COCl → CH₃COOH.Complete the equation
Method
Add hydrogen chloride as the second product.Reason
This conserves hydrogen and chlorine atoms.Working
CH₃COCl + H₂O → CH₃COOH + HCl.
Common misconception 3
Alkaline Hydrolysis of an Ester
Learner claim
Account for the base
View solution step by step
Split the ester
Method
Form an alcohol from the alkoxy part.Reason
Hydrolysis cleaves the acyl–oxygen linkage.Working
R'OH forms.Keep the acid deprotonated
Method
Form RCOO⁻, or RCOONa when the sodium salt is written.Reason
A carboxylic acid is deprotonated in the alkaline reaction mixture.Working
Products: R'OH + RCOONa.
Challenge 4
Ethanoyl Chloride with Ethanol
Nucleophile transfer
Replace chloride using ethanol
Hints
Hint 1: incoming group
Hint 2: coproduct
View solution step by step
Build the ester
Method
Replace the acyl chloride’s Cl by OC₂H₅.Reason
The alcohol acts as the oxygen nucleophile in acyl substitution.Working
Organic product: CH₃COOC₂H₅, ethyl ethanoate.Balance the equation
Method
Include hydrogen chloride.Reason
The eliminated H and Cl account for the remaining atoms.Working
CH₃COCl + C₂H₅OH → CH₃COOC₂H₅ + HCl.
Mind Stretchers
Mind stretcher 1Extension
Explain why chloro-substitution on a carboxylic acid chain can increase acidity.
Show Hint
Track whether hydrolysis conditions leave the acid protonated or as a carboxylate salt.
Show Answer
Mark scheme:
- Chlorine is electron-withdrawing (inductive effect).
- It stabilises the carboxylate ion RCOO⁻ by dispersing negative charge.
- Therefore dissociation is more favourable and the acid is stronger.
Mind stretcher 2: Comparing acidic and alkaline ester hydrolysisExtension
Question. Compare the organic products when ethyl ethanoate is heated with dilute acid and when it is heated with aqueous sodium hydroxide.
Show Hint
Both routes form ethanol; focus on the acid-derived product.
Show Answer
Acidic hydrolysis gives ethanol and ethanoic acid and is reversible. Alkaline hydrolysis gives ethanol and sodium ethanoate; carboxylate formation drives the reaction effectively to completion.