Atomic Orbitals: Energies and Shapes

Compare s, p and d orbitals by number, energy and shape, including the order of 4s and 3d.

  • GCE A-Level H2 Chemistry 9476-2027
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At A Level, an orbital is not a circular electron path. Orbital questions test (i) how many s, p and d orbitals exist, (ii) their relative energies and (iii) their shapes—including the exceptional d_z² shape. Use those ideas next in orbital filling and electron configuration. Return to the Atomic Structure hub when you need the full lesson sequence.

Definitions (Must Know)

A. Orbital

An orbital is a region of space around the nucleus in which there is a high probability of finding an electron. Each orbital can hold up to two electrons with opposite spins.

B. Shell (principal quantum number, n)

A shell is an energy level labelled by n = 1, 2, 3, ….

C. Subshell (s, p, d)

A subshell is a set of orbitals of the same type within a shell (e.g. 3p is a subshell inside the n = 3 shell).

Key Ideas (What Earns Marks)

  • s, p, d subshells contain 1, 3, 5 orbitals respectively.
  • Each orbital holds a maximum of 2 electrons → s holds 2, p holds 6, d holds 10.
  • For the same shell (n): s < p < d in energy (s is lowest energy).
  • For atomic structure questions you must know the relative order: 1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p.
Orbital shapes on labelled axes: a spherical s orbital; a two-lobed p-z orbital along z; d-xy, d-xz and d-yz with four lobes between their named axes; d-x-squared-minus-y-squared with four lobes along x and y; and d-z-squared with two lobes along z and a ring in the xy plane. Solid and hatched shading mark opposite wavefunction phases.
Each diagram sits on labelled axes with the nucleus at the origin. d(xy), d(xz) and d(yz) have lobes between their named axes, d(x²−y²) has lobes along x and y, and d(z²) has two lobes along z with a ring in the xy plane. Shading shows the sign (phase) of the wavefunction, not electric charge.

Detailed Explanations

A. How many orbitals exist in each subshell?

SubshellNumber of orbitalsMaximum electrons
s12
p36
d510

So for principal quantum numbers 1–3 (and the required 4s/4p):

Shell (n)Subshells present (A Level)Total orbitals in shellMaximum electrons in shell
11s12
22s, 2p48
33s, 3p, 3d918

You also need to know that 4s and 4p orbitals exist, and their relative energies appear in the common filling order used for electron configurations (see below).

B. Relative energies (what you need to memorise)

Two exam-safe rules for the multi-electron atoms considered here:

  1. Higher n generally means higher energy.
  2. For the same n: s < p < d.

The common energy order you use for electron configurations (up to 4p) is: 1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p

Energy level diagram showing the order 1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p
Energy level ladder showing the order of filling from lowest to highest energy.
Filling order is not a permanent energy ranking

Use 4s before 3d when building the configurations of neutral atoms. Once 3d is occupied, the relative energies change; transition-metal cations therefore lose 4s electrons before 3d electrons. Apply the configuration rules in Orbitals and Electron Configuration rather than assuming 4s is always lower in energy.

C. Shapes (what to write in “describe the shape” questions)

  • s orbital: spherical.
  • p orbital: two-lobed “dumbbell” (three orientations in space, so there are 3 p orbitals in a p subshell).
  • d orbitals: d_xy, d_xz, d_yz and d_(x²-y²) have four-lobed shapes. The fifth, d_z², has two lobes with a torus (ring) around the centre.

The different orientations do not create extra orbitals: a p subshell has three orbitals in total, and a d subshell has five.

Worked Examples

Modelled example 1

State p-Subshell Capacity

Core

Problem

State (a) the number of orbitals and (b) the maximum number of electrons in a p subshell.

Study the worked solution
  1. Recall the orbital count

    Method

    State that a p subshell contains three orbitals.

    Reason

    The three p orbitals have different spatial orientations.

    Working

    Number of p orbitals = 3.
  2. Calculate the capacity

    Method

    Multiply the orbital count by two electrons per orbital.

    Reason

    Each orbital holds a maximum of two electrons.

    Working

    Maximum electrons = 3 × 2 = 6.

Guided practice 2

Build the Capacity of the Third Shell

About 5 min

Problem

List the subshells present in the n = 3 shell and state the maximum number of electrons that can occupy the n = 3 shell.

Try this before viewing the solution

Hints

Hint 1: list the subshell types

For n = 3, include s, p and d subshells.

Hint 2: sum their capacities

Use capacities 2, 6 and 10.

View solution step by step
  1. List the subshells

    Method

    Attach the principal-shell number to s, p and d.

    Reason

    Those are the subshell types present in the n = 3 shell.

    Working

    3s, 3p and 3d.
  2. Add their capacities

    Method

    Add the maximum electron counts for one s, one p and one d subshell.

    Reason

    The shell capacity is the sum of all its subshell capacities.

    Working

    2 + 6 + 10 = 18 electrons.

Common misconception 3

Correct an Orbital-Energy Order

Find and correct the mistake

Learner attempt

Asked to put 3p, 4s, 3d and 4p in increasing energy order for a neutral atom, a learner writes 3p < 3d < 4s < 4p because every orbital with n = 3 must be lower than every orbital with n = 4. Identify the error and give the required order.

Choose the required middle order

Between 3p and 4p

View solution step by step
  1. Reject the single-number rule

    Method

    Use the memorised multi-electron energy ladder rather than sorting only by n.

    Reason

    Subshell type also affects relative energy, and 4s fills before 3d in the required neutral-atom sequence.

    Working

    3p < 4s < 3d < 4p.

Examiner practice 4

Describe the Five d Orbitals

3 marks

Problem

Describe the shapes of the five d orbitals without drawing them. [3 marks]

Try this before viewing the solution

View solution step by step
  1. Identify the four-lobed set

    2 marks

    Method

    Name d_xy, d_xz, d_yz and d_(x ⁽2 - y) ²) as four-lobed.

    Reason

    These four share the required four-lobed description, with different orientations.

    Working

    d_xy, d_xz, d_yz, d_(x ⁽2 - y) ²): four lobes.

  2. Describe the exception

    1 mark

    Method

    Describe d_(z ²) as two lobes along the z-axis with a torus around the centre.

    Reason

    This distinguishes its required shape from the other four d orbitals.

    Working

    d_(z ²): two axial lobes plus a central ring.

Challenge 5

Infer a Shell from Its Orbital Count

Minimal support

Problem

Within the required n = 1 to n = 3 shells, a complete shell contains nine orbitals in total. Deduce the subshells present, identify the shell and state its maximum electron capacity.

Try this before viewing the solution

Hints

Hint 1: build nine orbitals

Use s, p and d orbital counts of 1, 3 and 5.

Hint 2: convert orbitals to capacity

Each of the nine orbitals holds at most two electrons.

View solution step by step
  1. Reconstruct the subshell set

    Method

    Combine one s, three p and five d orbitals.

    Reason

    1 + 3 + 5 = 9, matching the total orbital count.

    Working

    The shell contains s, p and d subshells.
  2. Identify the shell

    Method

    Choose the first required shell that contains s, p and d.

    Reason

    The n = 3 shell contains 3s, 3p and 3d.

    Working

    The shell is n = 3.
  3. Find the capacity

    Method

    Multiply nine orbitals by two electrons per orbital.

    Reason

    Every orbital has the same maximum occupancy.

    Working

    9 × 2 = 18 electrons.

Common Mistakes

  • Treating every orbital in one shell as identical. The shell label n = 3 groups 3s, 3p and 3d, but it does not give them one energy or shape. In a many-electron atom, these subshells have different relative energies: a 3s orbital is spherical, a 3p orbital is two-lobed, and 3d orbitals have the d shapes shown above. Orbitals within one subshell, such as the three 3p orbitals, have the same energy but point in different directions. Compare the subshell letters as well as n before describing an orbital.
  • Describing orbitals as circular “electron orbits” around the nucleus.
  • Saying p has 2 orbitals (p has 3 orbitals) or d has 4 orbitals (d has 5 orbitals).
  • Drawing every d orbital as a four-lobed clover and forgetting the d_z² two-lobes-plus-torus shape.
  • Forgetting that a d subshell exists starting at n = 3 (3d is part of the n = 3 shell).
  • Mixing up filling order (4s before 3d) with removal from transition ions (4s removed first).

Check the distinction with n = 2: would a 2s orbital and a 2p orbital have the same energy and shape? Explain your answer before opening the check.

Check your answer

No. They share the n = 2 shell, but 2s and 2p are different subshells. In a many-electron atom, 2s is lower in energy than 2p; 2s is spherical while 2p is two-lobed. The three 2p orbitals have equal energy within that subshell and differ in orientation.

Then use the worked examples and practice below to apply orbital counts, shapes and energy order without relying on the shell number alone.

Exam Tips

  • If the question says “state the number”, just write: s = 1 orbital, p = 3, d = 5.
  • For “shape” questions, state spherical for s and two-lobed for p. For d, distinguish the four four-lobed orbitals from d_z² (two lobes and a torus).
  • If you use the energy order in a configuration answer, always write it from low → high energy (don’t invent a new order).

Mind Stretchers

Mind stretcher 1Extension

Explain why the 3p subshell contains three orbitals, but the 3s subshell contains only one orbital.

Show Answer

Mark scheme:

  • A p subshell consists of 3 orbitals (three orientations in space), while an s subshell consists of 1 orbital.
  • Therefore 3p has 3 orbitals but 3s has 1.

Mind stretcher 2Extension

A student says: “The 3d subshell is part of the 4th shell because 4s fills first.” Explain why this statement is wrong.

Show Answer

Mark scheme:

  • The label 3d means principal quantum number n = 3, so 3d belongs to the 3rd shell.
  • The fact that 4s fills before 3d is about relative energy, not which shell the subshell belongs to.
Syllabus and review details

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