Group 1: reactions and trends
Key idea: Group 1 metals form hydroxides and hydrogen with water. Reactivity increases down the group because the outer electron is farther from the nucleus and more easily lost.
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Guided lessons · coming soon
Guided lesson
Guided steps
- Compare water reactions, melting points and uneven density data.
- Match the three water observations to the metals.
- Explain increased reactivity using shells, shielding and electron loss.
- Predict rubidium’s properties using the trends.
- Predict caesium’s properties and judge the density prediction.
- Compare electron loss, electron gain and full outer shells.
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ContinueLithium, sodium and potassium form similar products with water, but react with different vigour. Use their observations and data to identify the Group 1 pattern, explain it through electron loss, and predict a member you have not met.
You need the Periodic Table position rules: occupied shells give the period, and outer electrons help identify the group.
Group 1: the alkali metals
Lithium, sodium and potassium are the Group 1 metals in this course. Start with the evidence from supervised teacher demonstrations. In each water test, a small piece of metal of similar size was added to water under the same conditions.
| Element | Electron arrangement | Melting point (°C) | Density (g/cm³) | With cold water |
|---|---|---|---|---|
| lithium | 2,1 | 181 | 0.53 | floats; fizzes steadily; slowly gets smaller |
| sodium | 2,8,1 | 98 | 0.97 | floats; melts into a silvery ball; fizzes rapidly and moves about |
| potassium | 2,8,8,1 | 63.5 | 0.89 | floats; melts; fizzes violently; may ignite; a lilac flame is seen |
What the data show:
- All three are soft enough to cut with a knife, and all have a low density: less than water (1.00 g/cm³), so they float. The densities do not change in one direction, so there is no density trend to learn.
- Melting point decreases down the group: 181 °C, then 98 °C, then 63.5 °C.
- Reaction with water becomes more vigorous down the group.
Each reaction gives hydrogen and a metal hydroxide solution. The lilac colour seen when potassium burns comes from potassium species in the flame; hydrogen alone does not give a lilac flame. Universal indicator added to the water afterwards turns purple, so the solution is alkaline. That is why Group 1 metals are called the alkali metals.
Lithium and potassium follow the same equation with Li or K in place of Na.
Why reactivity increases. A Group 1 atom reacts by losing its single outer electron to form a 1+ ion. Going down the group, the atom has more occupied shells. The outer electron is farther from the nucleus and more shielded by the inner shells, so it is held less strongly and lost more easily. The more easily the electron is lost, the more reactive the metal.
Guided practice 1
Identify Group 1 metals from observations
Problem
Equal small pieces of three Group 1 metals are added to water. Metal A fizzes steadily. Metal B melts into a ball and fizzes rapidly. With metal C, a lilac flame is seen as the reaction mixture ignites. Match A, B and C to lithium, sodium and potassium.
Use increasing vigour down the group
Hints
Hint 1
Trend
Compare each metal’s observed vigour with the table.
Hint 2
Distinctive signs
A molten ball suggests sodium; a lilac flame suggests potassium.
Show solution step by step
Rank the observations
Method
Arrange the reactions from least to most vigorous.
Reason
The pieces are similarly sized and the water conditions are the same, so the observations support this comparison.
Working
Answer
A < B < C in vigour.Match the metals
Method
Assign lithium, sodium and potassium in that order.
Reason
Reactivity increases down Group 1, and the molten ball and lilac flame agree.
Working
Answer
A = lithium; B = sodium; C = potassium.
Quick check
Use similarly sized, freshly cut pieces and the same water conditions. Different sizes or water temperatures would make vigour a less reliable comparison. A larger piece of lithium could fizz faster than a tiny piece of sodium.
Check your understanding 1 Explain the increasing reactivity
Lithium, sodium and potassium have one outer electron each. Explain why reaction with water becomes more vigorous down Group 1. Connect occupied shells, shielding, attraction and electron loss. Work on paper or in the optional notes.
Show answer
Each atom loses one outer electron to form a 1+ ion. Down the group there are more occupied shells; the outer electron is farther from the nucleus and more shielded by inner electrons. It is held less strongly and lost more readily, so reactivity increases. The common electron count explains similar products; easier loss explains the different vigour.
Worked example 2
Predict the properties of rubidium
Problem
Show full solution
Extend the melting-point trend
Method
Melting point falls down the group.Reason
181 °C, 98 °C, 63.5 °C is a steady decrease.Working
Answer
Rubidium is expected to melt below 63.5 °C.Extend the reactivity trend
Method
Its outer electron is even farther from the nucleus and more shielded by inner electrons.Reason
That electron is lost even more easily than potassium’s.Working
Answer
It is expected to react even more violently with water, forming rubidium hydroxide and hydrogen.Use the group pattern
Method
It has one outer electron, like the rest of Group 1.Reason
Losing that electron gives a 1+ ion.Working
Answer
Rb⁺State the limit
Working
Answer
These data cannot reliably predict its density: density does not change steadily from lithium to potassium.
Quick check
Check your understanding 2 Predict caesium
Caesium is below rubidium in Group 1. Predict its ion charge and how its melting point and water reaction compare with rubidium’s. Can the lithium–potassium density data give a reliable prediction of its exact density?
Show answer
Caesium forms a 1 + ion. Extending the trends predicts a lower melting point and a more vigorous water reaction than rubidium. The supplied density data do not give a reliable exact density.
Before you move on
Group 17 uses a different reaction pattern. The halogens and displacement lesson compares chlorine, bromine and iodine, and explains why their reactivity decreases down the group.
The noble gases and group comparisons lesson explains unreactivity and brings the three group patterns together.
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Syllabus and review details
- SEC G2 Science Chemistry component 2027 · 2027
Chemistry content structure and subject content, PDF pages 25–33
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