Cracking and Refinery Demand

Explain why refineries crack hydrocarbons, describe the conditions, and use atom conservation to deduce products.

  • SEC G3 Pure Chemistry 2027
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A refinery can separate the molecules in crude oil, but separation cannot turn a large molecule into a smaller one. Cracking changes molecules to help match the products of a refinery to what people need.

Separation or chemical change?

Fractional distillation separates a mixture into fractions with different boiling ranges. The molecules retain their chemical identities. Cracking breaks hydrocarbon molecules into smaller molecules: bonds break and new bonds form, so it is a chemical change.

Conditions and products

For the catalytic cracking studied here, vaporised hydrocarbons are heated to a high temperature and passed over a catalyst such as aluminium oxide, Al₂O₃, or silicon dioxide, SiO₂. The catalyst speeds up the reaction; it does not supply carbon or hydrogen to the products.

Cracking a larger alkane can produce a smaller alkane and an alkene:

C₁₀H₂₂ → [heat][catalyst] C₈H₁₈ + C₂H₄

Hydrogen may also be produced. This separate model equation shows how an alkane can form an alkene and hydrogen:

C₂H₆ → C₂H₄ + H₂
Cracking redistributes the atomsHigh temperature and a catalyst are used in catalytic cracking. In the first model equation, C10H22 forms C8H18 plus C2H4, retaining ten carbon and twenty-two hydrogen atoms. In a separate example, C2H6 forms C2H4 plus H2, retaining two carbon and six hydrogen atoms. These examples do not specify the full mixture from an industrial cracker.High temperature + catalystC₁₀H₂₂C₈H₁₈+C₂H₄Larger alkaneSmaller alkaneAlkeneAtom totals on each side: 10 C and 22 HC₂H₆C₂H₄+H₂AlkaneAlkeneHydrogenAtom totals on each side: 2 C and 6 H
Two model equations show different possible products. The first gives a smaller alkane and an alkene; the second gives an alkene and hydrogen. Both conserve carbon and hydrogen atoms.

These are examples, not a promise that every cracking reaction makes exactly two products in the same proportions. Real cracking produces a mixture. Each valid equation must conserve every type of atom.

Why a refinery needs cracking

Crude oil does not necessarily supply fractions in the proportions customers demand. If heavier fractions are in surplus while smaller fuel molecules and chemical feedstocks are in short supply, more fractional distillation cannot solve that mismatch. It only separates what is already present.

Cracking converts some surplus larger molecules into smaller molecules. Alkenes such as ethene are useful feedstocks for making plastics and other chemicals; smaller alkanes are useful fuels. The needed product is not always a fuel.

Work out a missing product

Guided practice 1

Cracking products (logic)

About 6 min

Guided equation

Decane is cracked to produce ethene and one alkane. Deduce the alkane and write one balanced cracking equation.

Use atom conservation to find the missing product

Carbon atoms in the missing product
Missing alkane

Hints

Hint 1: subtract atoms
Subtract the atoms in C₂H₄ from those in C₁₀H₂₂.
Hint 2: series check
Check that the remainder fits CₙH₂ₙ₊₂.
View solution step by step
  1. Conserve carbon

    Method

    Subtract the two carbon atoms in ethene from the ten in decane.

    Reason

    Cracking rearranges atoms; it does not create or destroy them.

    Working

    10-2 = 8 carbon atoms remain.
  2. Conserve hydrogen

    Method

    Subtract the four hydrogen atoms in ethene from the 22 in decane.

    Reason

    The missing product must contain all remaining hydrogen atoms.

    Working

    22-4 = 18, giving C₈H₁₈.
  3. Check and write the equation

    Method

    Confirm C₈H₁₈ is an alkane and write the products.

    Reason

    For n = 8, 2n + 2 = 18 and both sides now have identical atom totals.

    Working

    C₁₀H₂₂ → C₈H₁₈ + C₂H₄.

Try without prompts

Mind stretcher 1: Match a refinery supply to demandExtension

The table is an illustrative model, not measured refinery data. Supply and demand refer to the same total mass.

Fraction groupSupply / %Demand / %
Smaller-molecule fractions3050
Medium-molecule fractions3030
Larger-molecule fractions4020

Identify the surplus and shortage. Explain why another round of fractional distillation cannot correct them, and how cracking can help. Separately, deduce X in C₄H₁₀ → C₄H₈ + X. Would X decolourise bromine water in the usual test?

Show answer

The larger-molecule group has a surplus of twenty percentage points; the smaller-molecule group has a shortage of twenty. Distillation separates existing molecules without shortening them. Cracking can turn some larger molecules into smaller fuel molecules and alkenes. It need not convert all surplus material into exactly the desired products, so the table alone does not determine a cracking yield.

X is H₂: subtracting four C and eight H atoms leaves no C and two H. Hydrogen contains no C = C and does not decolourise bromine water in this test. Not every cracking product is an alkene.

Mind stretcher 2: Distinguish cracking from fractional distillationExtension

A learner says: “Cracking separates crude oil into fractions.” Replace this with an accurate sentence for cracking and one for fractional distillation.

Show answer

Cracking changes hydrocarbon molecules into smaller molecules using heat and, in the catalytic process studied here, a catalyst. Fractional distillation separates crude oil into fractions by boiling behaviour while preserving the molecules’ identities.

Bring the ideas together

Use molecule size and demand to explain why cracking is useful. Use atom conservation to check an equation. Heat and a catalyst help the reaction happen; they do not change the requirement for equal atom totals.

Practise and check

Use the Organic Chemistry topic check to practise and check your understanding.

Syllabus and review details

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