Transition Elements: Definition and Electron Configurations
Learn and apply Transition Elements: Definition and Electron Configurations in the published Chemistry course sequence.
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The core idea
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Definition and Electron Configurations: Orientation
This lesson makes the 9476 transition-element definition exam-safe: test the d-block atom or a cation for an incomplete d subshell, write first-row configurations with the chromium/copper exceptions, and explain the distinctive physical trends.
Use Orbitals and Electron Configuration as the prerequisite and the Transition Elements hub for the complete sequence.
Definitions (Must Know)
A. Transition element
A transition element is a d-block element whose atom has an incomplete d subshell, or which can form at least one cation with an incomplete d subshell.
- Scandium qualifies because Sc is [Ar]3d^14s^2: its atom has an incomplete d subshell.
- Copper qualifies because Cu²⁺ is [Ar]3d^9, even though Cu has a full 3d subshell.
- Zinc does not qualify because Zn and its usual Zn²⁺ ion have 3d¹⁰.
B. Cation configuration rule
For first-row transition elements, remove 4s electrons before 3d electrons when forming cations.
Detailed Explanations
A. Why 4s is removed before 3d (what to write)
When electrons are removed, the 4s electrons are lost first because after the 3d subshell begins to fill, the 4s electrons are higher in energy (and more easily removed) in the ions; therefore transition-metal cations are written without 4s electrons.
B. First-row configurations (core patterns)
General pattern:
- [Ar] 3dx 4s² for many elements
Common exceptions:
- chromium: Cr is [Ar] 3d⁵ 4s¹
- copper: Cu is [Ar] 3d¹⁰ 4s¹
C. Workflow: writing electron configurations for ions (exam method)
- Write the electron configuration for the neutral atom (use the Cr/Cu exceptions).
- Remove electrons from 4s first, then from 3d.
- Rewrite the ion configuration (typically with no 4s electrons for first-row transition-metal cations).
Mini example: Start with Fe: [Ar] 3d⁶ 4s². For Fe³⁺, remove 2 electrons from 4s and 1 from 3d → [Ar] 3d⁵.
D. Forming ions (worked patterns)
Example: iron
- Fe is [Ar] 3d⁶ 4s²
- Fe²⁺ is [Ar] 3d⁶
- Fe³⁺ is [Ar] 3d⁵
Example: copper
- Cu is [Ar] 3d¹⁰ 4s¹
- Cu⁺ is [Ar] 3d¹⁰
- Cu²⁺ is [Ar] 3d⁹
E. Why radii and first ionisation energies vary only slightly
Across the first transition series, proton number increases, but each additional electron enters the inner 3d subshell and increases shielding. The effective attraction felt by the outer electrons therefore changes less than a simple increase in nuclear charge suggests. State relatively invariant: small irregular changes remain because 3d electron pairing and subshell stability also vary.
F. Melting point and density compared with calcium
Most first-row transition elements have higher melting points than calcium because both 4s and available 3d electrons can contribute to stronger metallic bonding. They also have higher densities: their atoms have greater mass while their metallic radii do not increase correspondingly. This is a qualitative comparison; do not claim every value is identical across the series.
Worked Examples
Modelled example 1
Electron Configuration of Fe³⁺
Problem
Study the worked solution
Start from the atom
Method
Write Fe as [Ar]3d⁶4s².Reason
The neutral configuration fixes the available electrons.Working
Fe:[Ar]3d⁶4s².Remove electrons in ion order
Method
Remove two 4s electrons, then one 3d electron.Reason
4s electrons are removed before 3d when these ions form.Working
Fe³⁺:[Ar]3d⁵.
Common misconception 2
Why Zinc Is Excluded
Learner claim
Test both branches of the definition
View solution step by step
Test the atom
Method
Write Zn as [Ar]3d¹⁰4s^2.Reason
A species qualifies this branch only when its d subshell is incomplete.Working
The atom has a complete 3d¹⁰ subshell.Test the cation
Method
Remove the two 4s electrons to give Zn²⁺:[Ar]3d¹⁰.Reason
The usual cation also has a complete d subshell.Working
Neither branch supplies an incomplete d subshell.Apply the definition
Method
Exclude zinc as a transition element.Reason
Both its atom and usual cation fail the incomplete-d test.Working
Zn is not classed as a transition element.
Challenge 3
Electron Configuration of Cu²⁺
Configuration transfer
Remove from 4s first
Hints
Hint 1: first removal
Hint 2: second removal
View solution step by step
Use the exceptional atom
Method
Begin with [Ar]3d¹⁰4s¹.Reason
Copper is not 3d⁹4s² in its ground state.Working
Neutral Cu.Form the 2+ ion
Method
Remove 4s¹ and one 3d electron.Reason
Two electrons must be removed in the ionisation order.Working
Cu²⁺:[Ar]3d⁹.
Mind Stretchers
Mind stretcher 1: Explaining an unevenly flat trendExtension
Question. Across scandium to copper, a dataset shows small rises and falls in first ionisation energy but no large sustained increase. Explain why this still supports the description “relatively invariant”.
Show Hint
Compare the two opposing trends: increasing nuclear charge and increasing shielding by added 3d electrons.
Show Answer
Nuclear charge increases across the series and tends to increase first ionisation energy. Added electrons enter the inner 3d subshell and increase shielding, offsetting much of that greater attraction on the electron removed. Changes in 3d pairing and subshell stability cause small irregularities, so “relatively invariant” does not mean numerically constant.
Mind stretcher 2: Identifying a transition element from unfamiliar dataExtension
Question. Element X has atom configuration [Ar] 3d¹⁰4s^2 and forms only X²⁺ in the supplied chemistry. Element Y has atom configuration [Ar] 3d^54s^2 and forms Y²⁺ and Y³⁺. Decide which qualifies as a transition element, then predict which is more likely to show variable oxidation states.
Show Hint
Apply both branches of the definition: inspect the atom first, then any cation supplied.
Show Answer
X fails both branches: its atom is [Ar]3d¹⁰4s^2 and X²⁺ is [Ar]3d¹⁰, so neither has an incomplete d subshell. Y already qualifies through its [Ar]3d^54s^2 atom; its Y²⁺ and Y³⁺ ions are also 3d⁵ and 3d⁴. The two accessible ion configurations support variable oxidation states for Y.