Ionic bonding: forming ions and balancing charges
Form ions by electron loss and gain, show sodium chloride and magnesium chloride with dot-and-cross diagrams, and balance charges to write formulas.
On this page
How can neutral atoms form a compound containing charged particles? Follow the electrons to identify the ions, then name the electrostatic attraction that holds oppositely charged ions together. Electron transfer forms the ions; that attraction is the ionic bond.
Understand ionic bonding
Ionic bonding is the strong electrostatic force of attraction between oppositely charged ions (cations and anions).
Key ideas
- Metals form positive ions by losing electrons.
- Non-metals form negative ions by gaining electrons.
- Ionic bonds form after electron transfer between a metal and a non-metal.
- Ionic compounds form a giant ionic lattice (not molecules).
Form ions, then describe the attraction
- Losing electrons forms a positive ion; gaining electrons forms a negative ion.
- An ionic bond is the attraction between opposite charges.
- A compound’s total positive and negative charges balance.
Form ions using electron arrangements
The common ions considered here usually have a noble-gas electron arrangement. Losing or gaining electrons changes the charge, while the number of protons and the element’s identity stay the same. A full outer shell helps you predict common charges; it does not mean an isolated atom spontaneously gives away electrons.
- Cations (positive ions): metal atoms lose valence electrons.
- Example: lithium (2.1) loses 1 electron → Li⁺ (2).
- Example: aluminium (2.8.3) loses 3 electrons → Al³⁺ (2.8).
- Anions (negative ions): non-metal atoms gain electrons.
- Example: oxygen (2.6) gains 2 electrons → O²⁻ (2.8).
- Example: chlorine (2.8.7) gains 1 electron → Cl⁻ (2.8.8).
Use Electron arrangements to practise counting shell electrons.
Distinguish transfer from attraction
Ionic bonds are formed between metal ions and non-metal ions after electrons are transferred from the metal to the non-metal.
The attraction acts between opposite charges. It does not depend on which individual atom supplied an electron. In a solid, each ion attracts several oppositely charged neighbours.
Example: Sodium Chloride (NaCl)
- Sodium (2.8.1) transfers 1 valence electron to a chlorine atom (2.8.7).
- Na⁺ and Cl⁻ ions are formed.
- The oppositely charged ions attract each other strongly to form an ionic bond.
From ions to a lattice
Ions attract many neighbouring ions in a giant ionic lattice, rather than forming separate NaCl molecules. A formula such as NaCl states the simplest ion ratio. It does not name a molecule or a unique pair of bonded ions.
The next lesson, Ionic structures and properties, develops the lattice model and explains melting and electrical conductivity.
Track transferred electrons
The syllabus can test ionic bonding using dot-and-cross diagrams.
- Use dots and crosses to track the atoms from which the electrons came. Either symbol convention is valid if you use it consistently; the electrons themselves are identical.
- Show the ions in square brackets with the charge outside.
- Account for every transferred electron. For MgCl₂, the two electrons lost by magnesium supply one electron to each of two chlorine atoms.
- These diagrams omit the metal ion’s filled inner shells; Na⁺ and Mg²⁺ each have the electron arrangement 2.8.
Misconceptions to check
- Defining the bond as electron transfer. Transfer forms ions; ionic bonding is electrostatic attraction between oppositely charged ions.
- Writing “molecules of NaCl”. Use giant ionic lattice / formula unit.
- Forgetting charge balance when writing formulas (e.g., writing MgCl instead of MgCl₂).
Write formulas from charges
“Strong electrostatic attraction between oppositely charged ions.”
Write the ion charges, then balance to make total charge zero (e.g., Mg²⁺ needs two Cl⁻ → MgCl₂).
Worked examples
Modelled example 1
Describe Ionic Bonding (Magnesium Chloride)
Problem
Describe the formation of ionic bonds in magnesium chloride, MgCl₂.
Study the worked solution
Form the magnesium ion
Method
Transfer both magnesium valence electrons away.Reason
Magnesium has configuration 2.8.2 and reaches a full outer shell by losing two electrons.Working
Mg → Mg²⁺ + 2e⁻; configuration 2.8.2 → 2.8.Form two chloride ions
Method
Give one transferred electron to each of two chlorine atoms.Reason
Each chlorine atom needs one electron to change from 2.8.7 to 2.8.8.Working
2Cl + 2e⁻ → 2Cl⁻.Define the bond
Method
State the force after the ions form.Reason
Oppositely charged Mg²⁺ and Cl⁻ ions attract.Working
Strong electrostatic attraction holds the ions in a giant ionic lattice.
Guided practice 2
Predicting a Formula From Group Numbers
Problem
Element X is in Group 2 and element Y is in Group 17. Predict the formula of their ionic compound.
Balance total positive and negative charge
Hints
Hint 1: write both ion charges
Hint 2: make the total zero
View solution step by step
Predict the ions
Method
Use each group to predict electron loss or gain.Reason
Group 2 atoms lose two electrons; Group 17 atoms gain one.Working
Group 2 → X²⁺; Group 17 → Y⁻.Balance charges
Method
Use two Y ions for each X ion.Reason
1(2 +) + 2(1-) = 0, so the formula unit is electrically neutral.Working
X²⁺ + 2Y⁻ → XY₂.Write the simplest ratio
Working
XY₂.
Common misconception 3
Error Analysis (Fix the Formula)
Learner response
A student writes aluminium oxide as AlO because it contains aluminium and oxygen. Locate the first error, correct the formula and justify it using charges.
Test whether the proposed formula is neutral
View solution step by step
Locate the first error
Method
Check the net charge of one Al³⁺ and one O²⁻.Reason
With the stated Al³⁺ and O²⁻ ions, a 1:1 ratio has net charge + 1, so it cannot describe neutral aluminium oxide.Working
For one Al³⁺ and one O²⁻: + 3-2 = +1.Find the smallest balanced totals
Method
Use the lowest common multiple of 3 and 2.Reason
The smallest equal positive and negative charge totals are both 6.Working
2 × Al³⁺ = 6 + and 3 × O²⁻ = 6-.Correct the formula
Working
Al₂O₃.
For the solid-versus-molten worked explanation, continue to Ionic structures and properties.
Challenge 4
Identify the Bond Type
Evidence-to-model transfer
A metal atom transfers electrons to a non-metal atom. The resulting particles form a repeating lattice. Identify the bonding, name the particles and state the force holding the lattice together.
Build one connected explanation
Hints
Hint 1: follow the electrons
Electron transfer produces charged particles rather than neutral molecules.
Hint 2: name the lattice force
Ask what attraction acts between the resulting positive and negative particles.
View solution step by step
Infer particle formation
Method
Connect electron transfer to ion formation.Reason
The metal loses electrons to form cations; the non-metal gains them to form anions.
Working
Metal → cation; non-metal → anion.
Name the bonding and force
Working
This is ionic bonding: strong electrostatic attraction between oppositely charged ions in a giant lattice.
Try these independently
Compare the same compound in different states in Ionic structures and properties.
Mind stretcher 1: Reverse Charge ReasoningExtension
Question: An ionic compound has formula X₂O₃ where oxygen is O²⁻. What charge must ion X have?
Show Answer
Total negative charge from 3 oxygen ions: 3 × (-2) = -6.
Total positive charge must be +6 from 2 X ions, so each X is + 3.
Final: X³⁺.
Practise and check
See what you know across this topic, then go back to anything you got wrong.
Syllabus and review details
- SEC G3 Pure Chemistry 2027 · 2027
Content structure and subject content, PDF pages 9–24
Last reviewed: