Speed of Reaction

Rate of reaction: define change per unit time, choose a measurable quantity, calculate rates with units and interpret reaction graphs.

  • SEC G3 Pure Chemistry 2027
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Imagine collecting gas during a reaction. Measuring 20 cm³ tells you how much gas has collected; you also need the time interval to say how quickly it formed. Reaction rate connects the change with the time taken.

1. Definition

A. Speed (Rate) of Reaction

The speed of reaction (rate of reaction) is the change in amount of reactant used up or product formed per unit time.

B. Reactants and Products

  • Reactants: starting substances used up in a reaction.
  • Products: new substances formed in a reaction.

2. Key Ideas

  • In a simple reaction proceeding forwards, reactants are used up and products form. Measure a change that tracks this reaction.
  • Rate is always “change per time”, so it must have units (e.g., cm³/s, g/min, mol dm⁻³/s).
  • You can find rate by measuring an observable change (mass, gas volume, colour, pH, precipitate, etc.).
  • A reaction can be fast but produce very little product if the amount of reactant is small. Do not confuse rate with amount.
RepresentationWhat it tells you
Macroscopican observable quantity changes, such as gas volume increasing or mass decreasing
Particlereactant particles are converted into product particles during effective collisions
Symbolicrate is expressed as a change divided by a time interval, with a unit such as cm³ s⁻¹
Definition mark

Rate of reaction = amount of reactant used up or product formed per unit time.

3. Detailed Explanations

A. What “Per Unit Time” Means

An average rate describes a specified interval. Subtract the initial reading from the final reading and divide by the elapsed time. If the quantity decreases, such as mass when a gas escapes, use the positive amount lost.

average rate = change/(time taken)

Choose a quantity that tracks the reaction:

What changes?What you actually measureTypical unit
Gas producedvolume of gascm³ s⁻¹
Gas escapesmass decreasesg min⁻¹
Solution concentrationconcentration changesmol dm⁻³ s⁻¹
Fixed visible changetime to reach the same end-pointcompare reciprocal times, 1/t, in s⁻¹
A time is not itself a rate

Timing a fixed change lets you compare rates when the same change is reached in each experiment. The time has units of seconds; 1/t is a relative-rate measure in s⁻¹. Gas volume divided by time, such as cm³ s⁻¹, measures how much gas forms per second.

Same final gas volume, different initial rates

Gas volume against time for two illustrative reactions. Solid circles label the greater initial rate; dashed squares label the smaller initial rate. Both reach a horizontal plateau at 40 cubic centimetres.

Scroll across the graph to read all labels.

Gas volume against time for two illustrative reactions. Solid circles label the greater initial rate; dashed squares label the smaller initial rate. Both reach a horizontal plateau at 40 cubic centimetres.Gas volume against time for two illustrative reactions. Solid circles label the greater initial rate; dashed squares label the smaller initial rate. Both reach a horizontal plateau at 40 cubic centimetres.
Illustrative data: both reactions reach 40 cm³. The reaction with the greater initial rate produces gas more quickly at first and reaches its final volume sooner.
Open full-size graph
View figure data
Values for Same final gas volume, different initial rates
Time (s)Greater initial rateSmaller initial rate
000
10147
202513
303319
403725
503930
604034
704037
804039
904040
1204040

The illustrative graph compares reactions with the same final gas volume. Over the first 10 s, the solid curve rises by 14 cm³ and the dashed curve by 7 cm³. Their average rates over that interval are 14/10 = 1.4 and 7/10 = 0.70 cm³ s⁻¹. Both eventually reach 40 cm³. A faster start has not increased the final amount.

B. Try this next

Next, choose a practical measurement method in Measuring Reaction Rate. For gradients and tangents, use Reading Reaction-Rate Graphs. The particle explanations follow in:

4. Common Mistakes

  • Writing “rate is how fast a reaction happens” without stating the measurable change per unit time.
  • Giving only a time or amount when a rate is required. Include both the measurable change and “per unit time”.
  • Confusing rate with time taken: shorter time usually means faster rate, but you must state the condition (same amount of reactant/product).
  • Measuring the wrong thing (e.g., measuring “volume of air” instead of gas produced).
  • Not stating units.

5. Exam Tips

Quick unit check

Rate must have “per time” units. If your answer has no time unit, it is wrong.

  • If given data in a table, rate is often “change in volume/mass/concentration ÷ time”.
  • If asked for a method, write what you measure (e.g., “measure volume of gas every 10 s using a gas syringe”).
  • For a fixed end-point comparison, use the same measurable change. When testing a factor, change that factor and control the other relevant conditions.

6. Worked Examples

Modelled example 1

Calculate an Average Rate (Gas Volume)

Core

Problem

A reaction produces 48 cm³ of gas in 60 s. Calculate the average rate of gas production in cm³/s.
Study the worked solution
  1. Identify the measurable change

    Method

    Use the 48 cm³ increase in gas volume.

    Reason

    Average rate compares the amount of product formed with the elapsed time.

    Working

    Change = 48 cm³; time = 60 s.
  2. Divide change by time

    Method

    Calculate volume formed per second.

    Reason

    “Per unit time” means divide the measured change by the time interval.

    Working

    rate = 48/60 = 0.80 cm³ s⁻¹.
  3. Report the rate

    Method

    Include the volume-per-time unit and two significant figures.

    Reason

    The unit states what changed and the time basis; 0.80 matches the two significant figures in 48.

    Working

    0.80 cm³ s⁻¹.

Guided practice 2

Calculate an Average Rate (Mass Loss)

About 5 min

Problem

A reaction mixture loses 1.6 g in 4.0 minutes because a gas escapes. Calculate the average rate of mass loss in g/min.

Complete the change-per-time calculation

Rate unit

Hints

Hint 1: definition
Average rate is measured change divided by elapsed time.
Hint 2: unit
Keep minutes because the requested unit is g/min; no time conversion is needed.
View solution step by step
  1. Divide mass loss by time

    Method

    Divide 1.6 g by 4.0 min.

    Reason

    The escaping gas causes a measurable mass decrease per unit time.

    Working

    rate = 1.6/4.0 = 0.40.
  2. Attach the rate unit

    Method

    Report grams per minute.

    Reason

    The numerator is mass change and the denominator is time in minutes.

    Working

    0.40 g min⁻¹.

Common misconception 3

Spot the Bad Definition

Find and correct the mistake

Learner definition

A student writes, “Rate of reaction is how quickly a reaction finishes.” Identify what is missing and replace it with a precise definition.

Separate rate from completion time

Required measurable change
Required time language

View solution step by step
  1. Identify the vague quantity

    Method

    Reject “how quickly” without a measurable change.

    Reason

    A reaction can finish sooner because less reactant was present, even if its rate was not higher.

    Working

    Completion time alone mixes rate with amount.
  2. Give the measurable definition

    Method

    State change in reactant or product per unit time.

    Reason

    This identifies both what changes and the time denominator.

    Working

    Rate of reaction is the amount of reactant used up or product formed per unit time.

Guided practice 4

Choose a Suitable Observable Change

About 6 min

Method transfer

For magnesium reacting with dilute hydrochloric acid, state one suitable measurement for determining rate, name the apparatus where relevant and give the rate unit.

Connect reaction evidence to a rate

Observable change
Apparatus
Example rate unit

Hints

Hint 1: read the equation
The reaction produces H₂(g), so choose a property of that gas that changes with time.
View solution step by step
  1. Choose a product-linked observable

    Method

    Measure hydrogen volume as it forms.

    Reason

    Hydrogen is a gaseous product, so its increasing volume tracks product formation.

    Working

    Collect H₂ with a gas syringe at regular times.
  2. Define the rate quantity

    Method

    Calculate hydrogen volume formed per unit time.

    Reason

    The unit must identify both the measured change and the time basis.

    Working

    For example, rate in cm³ s⁻¹.

7. Mind Stretchers

Mind stretcher 1: Same Total Gas, Different RateExtension

Two experiments both produce 60 cm³ of gas in total. Experiment A reaches 60 cm³ in 30 s, Experiment B reaches 60 cm³ in 90 s. Which has the higher average rate? Explain.

Show Answer

Experiment A. For the same change (60 cm³), it takes less time, so rate is higher: 60/30 = 2.0 cm³/s vs 60/90 = 0.67 cm³/s.

Mind stretcher 2: “Fast” Does Not Mean “More”Extension

At 20 s, experiment X has collected 8 cm³ of gas; at 50 s it has collected 26 cm³. Experiment Y collects 12 cm³ over the same 30 s interval. Calculate and compare the average rates. X eventually produces 30 cm³ and Y 80 cm³: does Y’s greater final volume show that it had the faster rate over this interval?

Show Answer

For X, the interval change is 26 - 8 = 18 cm³, so the average rate is 18/30 = 0.60 cm³ s⁻¹. For Y, it is 12/30 = 0.40 cm³ s⁻¹. X has the greater rate over this interval. Y’s greater final gas volume describes the total amount, not the rate during the interval.

Practise and check

Practise and check

Use the Rate of Reactions topic check to practise definitions, units and measurement choices.

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